在做一个关于电子秤数据分析的程序，遇到数据分析问题，寻求帮助！

Question

第一组：
0,0,0,20,3340,4820,4860,4900,4900,4900,4900,9660,19000,19080,19600,19380,19600,19540,19380,19660,19840,19180,19560,19500,19440,19580,19480,19580,19500,19560,19460,19580,19520,19600,19540,19560,19540,19580,19560,19540,19520,19560,19540,19560,19540,19560,19580,19560数据重0开始：
“0,0,0,20,3340,4820,4860,4900,4900,4900,4900”相当于车辆第一组轮胎进入电子秤
“9660,19000,19080,19600,19380,19600,19540,19380,19660,19840,19180,19560,19500,19440,19580,19480,19580,19500,19560,19460,19580,19520,19600,19540,19560,19540,19580,19560,19540,19520,19560,19540,19560,19540,19560,19580,19560”相当于车辆第二组轮胎进入电子秤因此得出结论：此车2轴，车货总重19560，第一轴大概重量4900，第二轴大概重量19560-4900=14660第二组：
0,0,0,1900,5120,5180,5480,5480,5320,5480,18940,19900,19920,19920,19900,20000,19980,19960,20060,19700,19900,19760,20020,20160,20140,19800,20100,19500,20760,20380,20060,19920,20200,19700,20360,19640,19600,20420,19740,20240,19940,20020,20040,20040,20040,20060,20020,20080,20020,20080,20020,20080,20020,20060,20060,20060,20080,20040,20080,20060,20040数据重0开始：
“0,0,0,1900,5120,5180,5480,5480,5320,5480”相当于车辆第一组轮胎进入电子秤
“18940,19900,19920,19920,19900,20000,19980,19960,20060,19700,19900,19760,20020,20160,20140,19800,20100,19500,20760,20380,20060,19920,20200,19700,20360,19640,19600,20420,19740,20240,19940,20020,20040,20040,20040,20060,20020,20080,20020,20080,20020,20080,20020,20060,20060,20060,20080,20040,20080,20060,20040”相当于车辆第二组轮胎进入电子秤因此得出结论：此车2轴，车货总重20420，第一轴大概重量5480，第二轴大概重量20420-5480=14940第三组：
0,0,0,1480,5420,5780,5760,5760,5760,5760,5760,5760,5760,5740,5660,5620,5540,5560,5540,5540,5560,5560,5560,5620,6880,12960,13120,13140,13180,13140,13160,13160,13200,16560,19940,20140,20120,20240,20200,20220,20180,20200,20200,20220,20140,20200,20160,20240,20220,20200,20200,20180,20160,20200,20240,20200,20220,20220,20240,20220,20240,20300,20540,20520,20580,20580,20580,20560,20600,20620,20680,20560,20560,20460,20340,20280,20300,20280,20280,20280,20260,20800,28000,31500,31700,31700,31720,31660,31680,31700,32140,38500,42620,42620,42620,42400,42360,42340,42200,42260,43060,47160,51660,52320,52060,52420,52600,52420,52160,52180,52220,52240,52320,52780,52200,52320,52400,52380,52180,52460,52420,52360,52380,52340,52400,52360,52380,52360,52380,52360数据重0开始：
“0,0,0,1480,5420,5780,5760,5760,5760,5760,5760,5760,5760,5740,5660,5620,5540,5560,5540,5540,5560,5560,5560,5620,6880”相当于车辆第一组轮胎进入电子秤“12960,13120,13140,13180,13140,13160,13160,13200,16560”相当于车辆第二组轮胎进入电子秤“19940,20140,20120,20240,20200,20220,20180,20200,20200,20220,20140,20200,20160,20240,20220,20200,20200,20180,20160,20200,20240,20200,20220,20220,20240,20220,20240,20300,20540,20520,20580,20580,20580,20560,20600,20620,20680,20560,20560,20460,20340,20280,20300,20280,20280,20280,20260,20800”相当于车辆第三组轮胎进入电子秤“28000,31500,31700,31700,31720,31660,31680,31700,32140”相当于车辆第四组轮胎进入电子秤“38500,42620,42620,42620,42400,42360,42340,42200,42260,43060,47160”相当于车辆第五组轮胎进入电子秤“51660,52320,52060,52420,52600,52420,52160,52180,52220,52240,52320,52780,52200,52320,52400,52380,52180,52460,52420,52360,52380,52340,52400,52360,52380,52360,52380,52360”相当于车辆第六组轮胎进入电子秤因此得出结论：此车6轴，车货总重52380，第一轴大概重量5560，第二轴大概重量13200-5560=7640，第三轴大概重量20580-13200=7380，第四轴大概重量31700-20580=11120，第五轴大概重量42620-31700=10920，第六轴大概重量52360-42620=9740
不知道这个如何做成数学模型，或者如何查找规律？希望大家给出建议！！

Answer 1

哥哥我看回复看得蛋疼，《股票分析》都出来了，贴代码吧，大概就是这个意思：
        static void Main()
        {
            const double a = 800;      //正的变化率阀值，轮组进入
            const double b = -800;     //负的变化率阀值，轮组离开
            string inputstr = "0,0,0,1480,5420,5780,5760,5760,5760,5760,5760,5760,5760,5740,5660,5620,5540,5560,5540,5540,5560,5560,5560,5620,6880,12960,13120,13140,13180,13140,13160,13160,13200,16560,19940,20140,20120,20240,20200,20220,20180,20200,20200,20220,20140,20200,20160,20240,20220,20200,20200,20180,20160,20200,20240,20200,20220,20220,20240,20220,20240,20300,20540,20520,20580,20580,20580,20560,20600,20620,20680,20560,20560,20460,20340,20280,20300,20280,20280,20280,20260,20800,28000,31500,31700,31700,31720,31660,31680,31700,32140,38500,42620,42620,42620,42400,42360,42340,42200,42260,43060,47160,51660,52320,52060,52420,52600,52420,52160,52180,52220,52240,52320,52780,52200,52320,52400,52380,52180,52460,52420,52360,52380,52340,52400,52360,52380,52360,52380,52360";
            string[] inputsplit = inputstr.Split(new char[] { ',' });
            double[] inputdouble=new double[inputsplit.Length];//重量数据流
            for (int i = 0; i < inputsplit.Length; i++)
            {
                inputdouble[i] = Convert.ToDouble(inputsplit[i]);
            }
            double[] rate = new double[inputsplit.Length];     //变化率数据流，时间单位为1
            int[] signal = new int[inputdouble.Length];        //阀值量化信号数据流
            for (int i = 1; i < inputdouble.Length; i++)
            {
                rate[i] = inputdouble[i] - inputdouble[i - 1];
                if (rate[i] > a)
                    signal[i] = 1;
                else if (rate[i] < b)
                    signal[i] = -1;
                else
                    signal[i] = 0;
            }
            int bit = 0;
            List<int> index = new List<int>();
            for (int i = 1; i < inputdouble.Length; i++)
            {
                if (bit == 0 && signal[i] == 1)
                {
                    bit = 1;
                    index.Add(i - 1);           //轮组开始进入时的inputdouble下标
                }
                if (bit == 1 && signal[i] == 0)
                {
                    bit = 0;
                    index.Add(i);               //轮组稳定时的inputdouble下标
                }
            }
            index.Add(inputdouble.Length-1);     //因为你原始数据并不是整个过程，而是轮组进入的数据流，为了处理方便，记录最后一个数据的下标
            for (int i = 2; i < index.Count; i=i+2)
            {
                double avg = 0;
                for (int j = index[i - 1]; j <= index[i]; j++)
                    avg = avg + inputdouble[j];
                avg=avg/(index[i]-index[i-1]+1);              //取得重平均值
                Console.Write(((int)avg).ToString()+",");
            }
        }
输出结果：
5663，13157，20322，31757，42482，52348
对应于你最后一组数据。
阀值是关键，如果想做的更好一点，阀值看能不能动态确定。

Answer 2

static void Main() 
        { 
            const double a = 800;      //正的变化率阀值，轮组进入 
            const double b = -800;    //负的变化率阀值，轮组离开 
            string inputstr = "0,0,0,1480,5420,5780,5760,5760,5760,5760,5760,5760,5760,5740,5660,5620,5540,5560,5540,5540,5560,5560,5560,5620,6880,12960,13120,13140,13180,13140,13160,13160,13200,16560,19940,20140,20120,20240,20200,20220,20180,20200,20200,20220,20140,20200,20160,20240,20220,20200,20200,20180,20160,20200,20240,20200,20220,20220,20240,20220,20240,20300,20540,20520,20580,20580,20580,20560,20600,20620,20680,20560,20560,20460,20340,20280,20300,20280,20280,20280,20260,20800,28000,31500,31700,31700,31720,31660,31680,31700,32140,38500,42620,42620,42620,42400,42360,42340,42200,42260,43060,47160,51660,52320,52060,52420,52600,52420,52160,52180,52220,52240,52320,52780,52200,52320,52400,52380,52180,52460,52420,52360,52380,52340,52400,52360,52380,52360,52380,52360"; 
            string[] inputsplit = inputstr.Split(new char[] { ',' }); 
            double[] inputdouble=new double[inputsplit.Length];//重量数据流 
            for (int i = 0; i < inputsplit.Length; i++) 
            { 
                inputdouble[i] = Convert.ToDouble(inputsplit[i]); 
            } 
            double[] rate = new double[inputsplit.Length];    //变化率数据流，时间单位为1 
            int[] signal = new int[inputdouble.Length];        //阀值量化信号数据流 
            for (int i = 1; i < inputdouble.Length; i++) 
            { 
                rate[i] = inputdouble[i] - inputdouble[i - 1]; 
                if (rate[i] > a) 
                    signal[i] = 1; 
                else if (rate[i] < b) 
                    signal[i] = -1; 
                else 
                    signal[i] = 0; 
            } 
            int bit = 0; 
            List <int> index = new List <int>(); 
            for (int i = 1; i < inputdouble.Length; i++) 
            { 
                if (bit == 0 && signal[i] == 1) 
                { 
                    bit = 1; 
                    index.Add(i - 1);          //轮组开始进入时的inputdouble下标 
                } 
                if (bit == 1 && signal[i] == 0) 
                { 
                    bit = 0; 
                    index.Add(i);              //轮组稳定时的inputdouble下标 
                } 
            } 
            index.Add(inputdouble.Length-1);    //因为你原始数据并不是整个过程，而是轮组进入的数据流，为了处理方便，记录最后一个数据的下标 
            for (int i = 2; i < index.Count; i=i+2) 
            { 
                double avg = 0; 
                for (int j = index[i - 1]; j <= index[i]; j++) 
                    avg = avg + inputdouble[j]; 
                avg=avg/(index[i]-index[i-1]+1);              //取得重平均值 
                Console.Write(((int)avg).ToString()+","); 
            } 
        }

Answer 3

数据变化
x[i]= x1,x2....xi
b[i]= (x1-0) * 10/x1, (x2-x1) * 10/x2,... ...,(xi-xi-1)/xi。注xi为0时 bi=1
c[i]= |bi - 10| / n ; 注n为一个常量，例n可表示为max(x) 的10% 或者
此时得到的c数据应为 0,0,0,0,1,1,1,1,1,3,3,3,3,3,555555555,66666666666
判断不同值个数。算法优化
1、b[i]的取得，例如 bi = (xi+1 +  xi-1)/(xi * 2)等
2、n的取值情况，
3、c[i]的取得情况，例如c[i] =  [bi+1 + bi + bi-1 - 30]/n

Answer 4

b[i]= (x1-0) * 10/x1, (x2-x1) * 10/x2,... ...,(xi-xi-1)/xi。注xi为0时 bi=1
c[i]= |bi - 10| / n ; 注n为一个常量，例n可表示为max(x) 的10% 或者为什么是10这个参数？

Answer 5

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