xml写入同名节点的问题

Question

xml文件类似这样<StuRecord>
  <StdInfo>
    <ID>234</ID>
    <Name>王五</Name>
    <Record>78</Record>
  </StdInfo>
</StuRecord>使用的方法
public void SaveToXML(string id, string name, string record)
        {
            XmlDocument xmlDoc = new XmlDocument();
            xmlDoc.LoadXml("<StuRecord></StuRecord>");
            XmlNode root = xmlDoc.SelectSingleNode("StuRecord");            //创建一个新的StdInfo节点
            XmlElement stdInfo = xmlDoc.CreateElement("StdInfo");
            
            //ID节点
            XmlElement stdId = xmlDoc.CreateElement("ID");
            stdId.InnerText = id;
            stdInfo.AppendChild(stdId);            //Name节点
            XmlElement stdName = xmlDoc.CreateElement("Name");
            stdName.InnerText = name;
            stdInfo.AppendChild(stdName);            //Record节点
            XmlElement stdRecord = xmlDoc.CreateElement("Record");
            stdRecord.InnerText = record;
            stdInfo.AppendChild(stdRecord);            //添加StdInfo节点
            root.AppendChild(stdInfo);            //保存xml文件
            xmlDoc.Save("StuRecord.xml");
        }当再次调用这个方法时，只是把上次的给<StdInfo>给修改了，而不是创建一个新的<StdInfo>节点，我如果想每次调用都创建一个新的<StdInfo>，该如何修改

Answer 1

XmlDocument doc = new XmlDocument();
            try {
                doc.Load(LotteryHelper.RecordFileName);
                XmlNode root = doc.DocumentElement;                XmlElement xe1 = doc.CreateElement("Item");
                XmlAttribute node;
                XmlElement element;
                XmlNodeList nodeList = doc.GetElementsByTagName("Item");
                if (MultiGifts <= 1) {
                    for (int i = 0; i < nodeList.Count; i++) {
                        element = (XmlElement)nodeList.Item(i);
                        if ((element.GetAttribute("name") == m.UserName) && (element.GetAttribute("value") == m.UserNo)) {
                            ret = false;
                            break;
                        }
                    }
                }
                if (ret) {
                    node = doc.CreateAttribute("name");
                    node.InnerText = m.UserName;
                    xe1.Attributes.Append(node);                    node = doc.CreateAttribute("no");
                    node.InnerText = m.UserNo;
                    xe1.Attributes.Append(node);                    node = doc.CreateAttribute("gift");
                    node.InnerText = g.GiftName;
                    xe1.Attributes.Append(node);                    node = doc.CreateAttribute("dept");
                    node.InnerText = m.Dept;
                    xe1.Attributes.Append(node);                    node = doc.CreateAttribute("time");
                    node.InnerText = System.DateTime.Now.ToString();
                    xe1.Attributes.Append(node);
                    root.AppendChild(xe1);                    doc.Save(LotteryHelper.RecordFileName);
                }
            }
            catch {
                ret = false;
            }<?xml version="1.0" encoding="utf-8"?>
<Items>
  <Item name="a" no="138882**1" gift="参与奖" dept="物流" time="2010-11-8 10:28:21" />
  <Item name="何" no="138882**2" gift="参与奖" dept="发展" time="2010-11-8 10:28:23" />
  <Item name="杨" no="138882**3" gift="参与奖" dept="a部" time="2010-11-8 10:31:03" />
  <Item name="孔" no="138882**4" gift="参与奖" dept="b部" time="2010-11-8 10:31:05" />
</Items>

Answer 2

xmldoc.documentelement.ApendChild() 直接访问根元素集合对象，添 加子

Answer 3

public static void Insert(string path, string node, string element, string attribute, string value)
        {
            try
            {
                XmlDocument doc = new XmlDocument();
                doc.Load(path);
                XmlNode xn = doc.SelectSingleNode(node);
                if (element.Equals(""))
                {
                    if (!attribute.Equals(""))
                    {
                        XmlElement xe = (XmlElement)xn;
                        xe.SetAttribute(attribute, value);
                    }
                }
                else
                {
                    XmlElement xe = doc.CreateElement(element);
                    if (attribute.Equals(""))
                    {
                        xe.InnerText = value;
                    }
                    else
                    {
                        xe.SetAttribute(attribute, value);
                    }
                    xn.AppendChild(xe);
                }
                doc.Save(path);
            }
            catch { }
        }
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