C#中的复数问题（请教）

Question

C#中两个以上复数的加减乘除如何实现啊？
请高手赐教！

Answer 1

private void btn_Click(object sender, EventArgs e) 
{ 
complex complex_a = new complex(1.0, 1.0); 
complex complex_b = new complex(2.0, 2.0); 
MessageBox.Show("加法运算结果：" + complex_a.complex_add(complex_b).ToString()); 
MessageBox.Show("减法运算结果：" + complex_a.complex_minus(complex_b).ToString() ); 
MessageBox.Show("乘法运算结果：" + complex_a.complex_multi(complex_b).ToString() ); 
MessageBox.Show("除法运算结果：" + complex_a.complex_divide(complex_b).ToString()); 
} 
public class complex 
{ 
//复数中的实部 
private double complex_real; 
//复数中的虚部 
private double complex_imagin; //构造函数 
public complex(double r, double i) 
{ 
complex_real = r; 
complex_imagin = i; 
} //重写ToString()方法 
public override string ToString() 
{ 
return this.complex_real + "+" + this.complex_imagin + "i"; 
} //复数加法运算 
public complex complex_add(complex c) 
{ 
//取得加法运算后的实部 
double complex_real = this.complex_real + c.complex_real; //取得加法运算后的虚部 
double complex_imagin = this.complex_imagin + c.complex_imagin; //返回一个复数类 
return new complex(complex_real,complex_imagin); 
} //复数减法运算 
public complex complex_minus(complex c) 
{ 
//取得减法运算后的实部 
double complex_real = this.complex_real - c.complex_real; //取得减法运算后的虚部 
double complex_imagin = this.complex_imagin - c.complex_imagin; //返回一个复数类 
return new complex(complex_real, complex_imagin); 
} //乘法运算 
public complex complex_multi(complex c) 
{ 
//取得乘法运算后的实部 
double complex_real = this.complex_real * c.complex_real - this.complex_imagin * c.complex_imagin; //取得乘法运算后的虚部 
double complex_imagin = this.complex_real * c.complex_imagin + this.complex_imagin * c.complex_real; //返回一个复数类 
return new complex(complex_real, complex_imagin); 
} //除法运算结果 (a+bi)/(c+di)=(a+bi)(c-di)/(c+di)(c-di) 
public complex complex_divide(complex c) 
{ 
//取得(c+di)(c-di)的值 
double d = c.complex_real * c.complex_real + c.complex_imagin * c.complex_imagin; //取得除法运算后的实部 
double complex_real = (this.complex_real * c.complex_real + this.complex_imagin * c.complex_imagin) / d; //取得除法运算后的虚部 
double complex_imagin = (this.complex_real * (-c.complex_imagin) + this.complex_imagin * c.complex_real) / d; //返回一个复数类 
return new complex(complex_real, complex_imagin); 
} 
}