多线程问题,两个线程 但界面只有一个lable显示

Question

简单写了下 
 public partial class Form1 : Form
    {
        public Form1()
        {
            InitializeComponent();
        }
        public delegate void mydelegate();
        public delegate void mydelegate2(string lblid,int i);
        private object lockObj = new object();
        int threadid;
        int widht = 11;
        private void Form1_Shown(object sender, EventArgs e)
        {
        }
        private void mydelegatePro()
        {
            widht += 10;
            threadid++;
            Label lbl = new Label();
            lbl.Name = "lbl" + threadid.ToString();
            lbl.Top = widht;
            this.Controls.Add(lbl);
            Application.DoEvents();
          
        }
        private void mydelegatePro2(string lblid,int i)
        {
            Control con = this.Controls[lblid];
            Label lbl = (Label)con;
            lbl.Text = i.ToString();
            
            Application.DoEvents();
        }
       
        private void NewThread()
        {
            this.BeginInvoke(new mydelegate(mydelegatePro));            string lblid = "lbl" + threadid.ToString();
            int i = 0;
            while (true)
            {
                i++;
                lock (lockObj)
                {                    this.BeginInvoke(new mydelegate2(mydelegatePro2), new object[] { lblid, i });                    
                }
                Thread.Sleep(200);
                if (i >= 10) break;
            }
          
        }
        private void button1_Click(object sender, EventArgs e)
        {
    
            Thread thread = new Thread(new ThreadStart(NewThread));
            thread.IsBackground = true;
            thread.Start();
            Thread thread2 = new Thread(new ThreadStart(NewThread));
            thread2.IsBackground = true;
            thread2.Start();
        }    
    }

Answer 1

问题出在threadid的使用上threadid++;
string lblid = "lbl" + threadid.ToString();threadid有可能是一样的。同为2

Answer 2

通地调试跟踪 确保threadid不一样的时候也 无法显示第二个Label

Answer 3

Label lbl = new Label();widht += lbl.Height;
lbl.Top = widht;

Answer 4

用begininvoke，是不是有问题。