怎样取得xml文件中节点的值？

Question

你的xml文件必须有一个根节点，如下：
<products>
   <product>
       <id>111</id>
       <name>abc</name>
   </product>
   <product>
       <id>222</id>
       <name>eee</name>
   </product>
</products>
解析程序如下：
import javax.xml.parsers.*;
import org.w3c.dom.*;public class xmltest
{
public static void  main(String args[]){
    try{
       DocumentBuilderFactory factory = DocumentBuilderFactory.newInstance();
       DocumentBuilder builder=factory.newDocumentBuilder();
       Document doc=builder.parse("test.xml");
       doc.normalize();
       NodeList links =doc.getElementsByTagName("product");
       for (int i=0;i<links.getLength();i++){
            Element link=(Element) links.item(i); 
            if (link.getElementsByTagName("id").item(0).getFirstChild().getNodeValue().toString().equals("222"))
                      System.out.println("name:"+link.getElementsByTagName("name").item(0).getFirstChild().getNodeValue());
       }
     }catch(Exception e){}
  }
}

Answer 1

javax.xml.parsers.DocumentBuilderFactory dbf=javax.xml.parsers.DocumentBuilderFactory.newInstance();
      javax.xml.parsers.DocumentBuilder db=dbf.newDocumentBuilder();
      org.w3c.dom.Document document=db.parse(request.getRealPath("xxx.xml"));
      org.w3c.dom.Element element=document.getDocumentElement();
      org.w3c.dom.NodeList nl=element.getElementsByTagName("product");
    for(int i=0;i<nl.getLength();i++) {
      org.w3c.dom.Element ele = (org.w3c.dom.Element) nl.item(i);
      org.w3c.dom.NodeList nl1=ele.getElementsByTagName("id");
      if(nl1.getLength()==1) {
        org.w3c.dom.Element e=(org.w3c.dom.Element)nl1.item(0);
        org.w3c.dom.Text text=(org.w3c.dom.Text)e.getFirstChild();
System.out.println(text);
      }
    }
俺的文档里有，如下：
http://www.csdn.net/develop/read_article.asp?id=17818

Answer 2

用XSLT:
XML FILE :
<products>
   <product>
       <id>111</id>
       <name>abc</name>
   </product>
   <product>
       <id>222</id>
       <name>eee</name>
   </product>
</products>
XSLT:
<?xml version = "1.0" encoding = "UTF-8"?>
<xsl:transform xmlns:xsl = "http://www.w3.org/1999/XSL/Transform" version = "1.0">
<xsl:template match = "products">
<xsl:element name = "NAME">
<xsl:for-each select = "./product">
<xsl:variable name = "id" select = "./id"/>
<xsl:if test = "$id=222">
<xsl:value-of select = "./name"/>
</xsl:if>
</xsl:for-each>
</xsl:element>
</xsl:template>
</xsl:transform>

Answer 3

public static Document parseXML(String input)
        throws UnsupportedEncodingException, SAXException, IOException, ParserConfigurationException
    {
        DocumentBuilder builder = null;
        synchronized(com.justnorth.util.Tool.class)
        {
            if(docFactory == null)
                docFactory = DocumentBuilderFactory.newInstance();
        }
        builder = docFactory.newDocumentBuilder();
        //BufferedReader br = new BufferedReader(new InputStreamReader(input, "gb2312"));
        InputSource is = new InputSource(new StringReader(input));
        return builder.parse(is);
    }
    public static String getAttribute(Element elem, String name)
    {
        Attr attr = elem.getAttributeNode(name);
        return attr != null ? attr.getValue() : null;
    }    public static String getValue(Node elem)
    {
        String val = null;
        NodeList nlist = elem.getChildNodes();
        for(int i = 0; i < nlist.getLength(); i++)
        {
            Node child = nlist.item(i);
            if(child.getNodeType() == 3)
            {
                String sval = child.getNodeValue();
                if(sval.trim().length() > 0)
                    val = sval;
                continue;
            }
            if(child.getNodeType() != 4)
                continue;
            val = child.getNodeValue();
            break;
        }        if(val != null)
        {
            if(val.startsWith("\n"))
                val = val.substring(1);
            if(val.endsWith("\n"))
                val = val.substring(0, val.length() - 1);
        }
        return val;
    }

Answer 4

请看 
   public String getResponse(String inputReq)
    {
      //Parse who get the Information
      try
      {
       SAXBuilder builder = new SAXBuilder();
       Document InfoRequest = builder.build(new StringReader(inputReq));
     Element InfoRequestRoot = InfoRequest.getRootElement();
     String providerID = InfoRequestRoot.getAttribute("PROVIDERID").getValue();
     String clientID = InfoRequestRoot.getChild("CLIENTID").getText();
     String clientName = InfoRequestRoot.getChild("CLIENTNAME").getText();
     String fileID = InfoRequestRoot.getChild("FILEID").getText();
     String fileTitle = InfoRequestRoot.getChild("FILETITLE").getText();
    
     Element ResponseRoot = new Element("RESPONSE");
     Attribute response = new Attribute("PROVIDERID","1");
     ArrayList responseAttribute = new ArrayList();
     responseAttribute.add(response);
    
     ResponseRoot.setAttributes(responseAttribute);
     ResponseRoot.addContent(new Element("CLIENTID").setText(clientID));
     ResponseRoot.addContent(new Element("CLIENTNAME").setText(clientName));
     ResponseRoot.addContent(new Element("FILEID").setText(fileID));
     ResponseRoot.addContent(new Element("FILETITLE").setText(fileTitle));
     ResponseRoot.addContent(new Element("STATE").setText("READ"));    
     Document ResponseDoc = new Document(ResponseRoot);
     XMLOutputter outputter = new XMLOutputter(" ",true);
     return outputter.outputString(ResponseDoc);   
    
      }
      catch(Exception e)
      {
       e.printStackTrace(System.out);
       return "Error";
      }
    }