错误:
HTTP Status 404 - /myweb/servlet/mypackage.forky--------------------------------------------------------------------------------type Status reportmessage /myweb/servlet/mypackage.forkydescription The requested resource (/myweb/servlet/mypackage.forky) is not available.
--------------------------------------------------------------------------------Apache Tomcat/6.0.18jsp源代码:
      <jsp:forward page="servlet/mypackage.forky" >
        <jsp:param name="username"  value="<%=username %>" />
      </jsp:forward>web.xml
<web-app>
  <welcome-file-list>
    <welcome-file>login.html</welcome-file>
  </welcome-file-list>
  <servlet>
    <servlet-name>ValidateServlet</servlet-name>
    <servlet-class>mypackage.validate</servlet-class>
  </servlet>
  <servlet-mapping>
    <servlet-name>ValidateServlet</servlet-name>
    <url-pattern>/mybackage</url-pattern>
  </servlet-mapping>
  
  <servlet>
  <servlet-name>forkytServlet</servlet-name>
    <servlet-class>mypackage.forky</servlet-class>
  </servlet>
  <servlet-mapping>
    <servlet-name>forkytServlet</servlet-name>
    <url-pattern>/mybackage</url-pattern>
  </servlet-mapping> 
</web-app>

解决方案 »

  1.   


      <servlet-name>forkytServlet </servlet-name>
        <servlet-class>mypackage.forky </servlet-class>
      </servlet>
      <servlet-mapping>
        <servlet-name>forkytServlet </servlet-name>
        <url-pattern>/mypackage.forky </url-pattern>
      </servlet-mapping> servlet的使用可以参考我们的教程:
    http://family168.com/tutorial/jsp/html/index.html
      

  2.   

    <servlet>
      <servlet-name>forkytServlet </servlet-name>
        <servlet-class>servlet/mypackage.forky </servlet-class>
      </servlet>
      <servlet-mapping>
        <servlet-name>forkytServlet </servlet-name>
        <url-pattern>/mybackage </url-pattern>
      </servlet-mapping>