如何把一个字符串按指定长度分割成字符串数组:
如:
String name=new String("kensingle");如:按4个字符分:int n=name.length; 得到9位double r=new Integer(n).doubleValue()/4; 得到2.25如:得到有小数位2.25, 就取3String [] nameList=new String[3];nameList[0]="kens";
nameList[1]="ingl";
nameList[2]="e";比较菜!求大家帮忙!一时没思路!
如:
String name=new String("kensingle");如:按4个字符分:int n=name.length; 得到9位double r=new Integer(n).doubleValue()/4; 得到2.25如:得到有小数位2.25, 就取3String [] nameList=new String[3];nameList[0]="kens";
nameList[1]="ingl";
nameList[2]="e";比较菜!求大家帮忙!一时没思路!
nameList[i]=str.subString(i*4,i*4+4);
if(i!=iLen-1)
nameList[i]=str.subString(i*4,i*4+4);
else nameList[i]=str.subString(i*4,str.length());==========
上面有点错误!没考虑空串的情况~
public static void main(String[] args){
String name = new String("kensingle");
int n = name.length();
double r = new Integer(n).doubleValue() / 4;
int num = 0;
if(r > (int)r){
num = (int)r + 1;
}
String str[] = new String[num]; int j = 0;
int k = 0;
for(int i = 0; i < num; i ++){
k = j + 4;
if(k <= name.length()){
str[i] = name.substring(j, k);
j = k;
}
else{
str[i] = name.substring(j, name.length());
}
System.out.println(str[i]);
}
}
}ok
if (gap < 0) {
return null;
}
int length = str.length();
int num = (length - 1)/gap + 1;
String[] result = new String[num];
for(int i = 0, begin = 0, end = 0; i < num; i++) {
end = begin + gap < length ? begin + gap : length ;
result[i] = str.substring(begin, end);
begin = end;
}
return result;
}