客户端发消息的简化: String s=sendtext.getText().trim();//从输入框得的要发送的消息
byte[] data=s.getBytes();
sendPacket=new
DatagramPacket(data,s.length(),InetAddress.getByName(theip),sendPort);
sendSocket.send(sendPacket);}//theip是服务器的IP地址服务器受消息的简化 if(receiveSocket!=null){
receiveSocket.receive(receivePacket);
byte[] data=receivePacket.getData();
String receivedString=new String(data,0).trim();
}
服务器发消息的简化
byte[] databyte=new byte[512];
receivedString.getBytes(0,receivedString.length(),databyte,0);
sendPacket=new DatagramPacket(databyte,receivedString.length (),InetAddress.getByName(receiverip),5001);
sendSocket.send(sendPacket);
客户受消息的简化
receivePacket=new DatagramPacket(array,array.length);
receiveSocket.receive(receivePacket);
byte[] data=receivePacket.getData();
received=new String(data,0,data.length);
received.trim();
我该怎么编码啊
byte[] data=s.getBytes();
sendPacket=new
DatagramPacket(data,s.length(),InetAddress.getByName(theip),sendPort);
sendSocket.send(sendPacket);}//theip是服务器的IP地址服务器受消息的简化 if(receiveSocket!=null){
receiveSocket.receive(receivePacket);
byte[] data=receivePacket.getData();
String receivedString=new String(data,0).trim();
}
服务器发消息的简化
byte[] databyte=new byte[512];
receivedString.getBytes(0,receivedString.length(),databyte,0);
sendPacket=new DatagramPacket(databyte,receivedString.length (),InetAddress.getByName(receiverip),5001);
sendSocket.send(sendPacket);
客户受消息的简化
receivePacket=new DatagramPacket(array,array.length);
receiveSocket.receive(receivePacket);
byte[] data=receivePacket.getData();
received=new String(data,0,data.length);
received.trim();
我该怎么编码啊
解决方案 »
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出现问题的原因可能是3个机器的默认编码不一致造成的.运行以下下面的程序,看3个机器的默认编码是否一样:
//Encode.java
public class Encode {
public static void main(String args[]) {
System.out.println(System.getProperty("file.encoding"));
}
}
最好的做法是所有程序在编码和解码是采用同样的编码方式;
也就是将所有涉及到网络通信的地方做如下修改:
s.getBytes() 改为 s.getBytes("GB2312");
new String(data,0,data.length); 改为 new String(data,0,data.length,"GB2312");注意这样修改后,需要捕获异常,做异常处理.