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Question

这不就是猜数字的游戏吗，很多手机上有！！！这和Jbuilder什么关系？？？应该是求一个算法吧！！！挺有创意的，自己想吧，帮不上你！！！

Answer 1

猜数字游戏的算法,google上搜去吧多的是

Answer 2

给你一个我写的C程序，很容易转成java代码
//猜数字游戏#include<iostream.h>
#include<stdlib.h>
#include<conio.h>
#include<time.h>int N;
char result[10]="123456789";
int a,b;
void  product()
{
    char temp;
    int t;    srand(time(0));    //产生真正的随机数    for(int i=0;i<N;i++)
    {
        t=rand()%9;
        if(t!=i)
        {
            temp=result[i];
            result[i]=result[t];
            result[t]=temp;
        }
    }
}void check(char *user)
{
    a=b=0;
    for(int i=0;i<N;i++)
    {
        for(int j=0;j<N&&*(result+i)!=*(user+j);j++);
        if(j==i)
            a++;
        else if(j!=N)
            b++;
    }
}
void input(char *user)
{
    char ch;
    int k;
    cout<<"Please input "<<N<<" numbers:"<<endl;
    for(int i=0;i<N;i++)
    {
        do
        {
            k=0;
            ch=getch();
            for(int j=0;j<i&&!k;j++)
            {
                if(*(user+j)==ch)
                    k=1;
            }
        }while(ch<'1'||ch>'9'||k);
        *(user+i)=ch;
        cout<<ch<<flush;
    }
            
}
void main()
{
    char *user;
    int count;
    char key;
    cout<<"Welcome to use GuessNumber game!"<<endl;
    do
    {
        cout<<"Please select the difficulty:"<<flush;
        do
        {
            N=getch()-'0';
        }while(N<1);
        cout<<N<<endl;        user=new char[N];
    
        count=0;
        product();
        do
        {
            input(user);
            check(user);
            cout<<'\t'<<a<<'A'<<b<<'B'<<endl;
            count++;
        }while(a!=N);
        cout<<"Congratulations!You get it by guessing for "<<count<<" times."<<endl;
        cout<<"Would you like to try again?(y/n) "<<flush;
        do
        {
            key=getch();
        }while(key!='y'&&key!='n');
        cout<<key<<endl;
    }while(key=='y');
    cout<<"Thanks for using!"<<endl;}

Answer 3

如果楼主用了楼上的c程序.那么就得转化成Java了,
^_^...赶紧搜索以前得相关程序吧.我有的回答的啊!