<a id="program" herf="javascript:void(0)" onclick="program();"><span>未</span></a>
<a id="program-link" href="url"style="display: none;"></a>
function program(){
var id = ${ticketId};
var ahref = $('#program-link').attr("href");
$('#program-link').attr("href", ahref + "/" + id);
$('#program-link').怎么提交 让他在本页面请求url地址?
$('#program-link').click();
$('#program-link').attr("href", ahref);
}
求解答 JavaScript函数URL
<a id="program-link" href="url"style="display: none;"></a>
function program(){
var id = ${ticketId};
var ahref = $('#program-link').attr("href");
$('#program-link').attr("href", ahref + "/" + id);
$('#program-link').怎么提交 让他在本页面请求url地址?
$('#program-link').click();
$('#program-link').attr("href", ahref);
}
求解答 JavaScript函数URL
如果只是一个提交的话直接获取节点然后submit应该就可以了。。
如果楼主想自己生成url请求的话,
xmlhttp=new ActiveXObject("Msxm12.XMLHTTP");
xmlhttp.onreadystatechange=requestAjax;
xmlhttp.open( "GET", url , true );
xmlhttp.send( null );
var id = ${ticketId};
var ahref = $('#program-link').attr("href");
$('#program-link').attr("href", ahref + "/" + id);
$('#program-link').怎么提交 让他在本页面请求url地址?
//加上
$('#program-link').attr("target","tagFrame");$('#program-link').click();
$('#program-link').attr("href", ahref);
}