HashMap a=new HashMap();
a.put("111", new User("111"));
a.put("11", new User("11"));
a.put("1", new User("1"));
Collection e=a.values();
List list=new ArrayList();
for(Object o: e){
list.add(o);
}
Set set=a.keySet();
List use=new ArrayList();
List pwd=new ArrayList();
Scanner s = new Scanner(System.in);
System.out.println("请输入用户名:");
String userName = s.next();
System.out.println("请输入密码:");
String pwd1 = s.next();
for(Object o:list){
for(Object o1:set){
use.add(o1);
pwd.add(o);
}
}
if(use.equals(userName)&&pwd.equals(pwd1)){
System.out.println("登录成功");
showControl();
}else {
System.out.println("登录失败,");
showLogin();
}
}
老是登陆失败···请大虾们帮我看看
a.put("111", new User("111"));
a.put("11", new User("11"));
a.put("1", new User("1"));
Collection e=a.values();
List list=new ArrayList();
for(Object o: e){
list.add(o);
}
Set set=a.keySet();
List use=new ArrayList();
List pwd=new ArrayList();
Scanner s = new Scanner(System.in);
System.out.println("请输入用户名:");
String userName = s.next();
System.out.println("请输入密码:");
String pwd1 = s.next();
for(Object o:list){
for(Object o1:set){
use.add(o1);
pwd.add(o);
}
}
if(use.equals(userName)&&pwd.equals(pwd1)){
System.out.println("登录成功");
showControl();
}else {
System.out.println("登录失败,");
showLogin();
}
}
老是登陆失败···请大虾们帮我看看
List pwd=new ArrayList();
if(use.equals(userName)&&pwd.equals(pwd1))
你这是在干嘛?List 和 String 怎么可能equal?当然”登陆失败“啦
就是这里我不知道该怎么写
无从下手,各位大侠帮帮忙该怎么写
}
use.contains(useName)表示集合use中是否包含了useName这个元素,另外建议你用集合类的时候最好用泛型,JDK5.0的新特性。