假设有两个字符串数组:
String[] s1={"狐狸","狗熊","香蕉","猴子","熊猫","大象","苹果"};
String[] s2={"西瓜","香蕉","蛋糕","苹果","长颈鹿","袋鼠","狗熊","鲸鱼"};
如何取他们的交集?
String[] s1={"狐狸","狗熊","香蕉","猴子","熊猫","大象","苹果"};
String[] s2={"西瓜","香蕉","蛋糕","苹果","长颈鹿","袋鼠","狗熊","鲸鱼"};
如何取他们的交集?
调试欢乐多
String[] s2={"西瓜","香蕉","蛋糕","苹果","长颈鹿","袋鼠","狗熊","鲸鱼"};
ArrayList al=new ArrayList(Arrays.asList(s1));
al.retainAll(Arrays.asList(s2)); // al中的结果就是交集了.
System.out.println("交集:"+al);
运行结果:
交集:[狗熊, 香蕉, 苹果]
public class Test{
public static void main(String[] args){
String[] s1={"狐狸","狗熊","香蕉","猴子","熊猫","大象","苹果"};
String[] s2={"西瓜","香蕉","蛋糕","苹果","长颈鹿","袋鼠","狗熊","鲸鱼"};
ArrayList a1=new ArrayList(Arrays.asList(s1));
boolean flag=true;
for(int i=0;i<s2.length;i++){
for(int j=0;j<a1.size();j++){
if(s2[i].equals(a1.get(0))){
flag=false;
}
}
if(flag){
a1.add(s2[i]);
}
flag=false;
}
System.out.println(a1);
}
}
[狐狸, 狗熊, 香蕉, 猴子, 熊猫, 大象, 苹果, 西瓜]
public class Test{
public static void main(String[] args){
String[] s1={"狐狸","狗熊","香蕉","猴子","熊猫","大象","苹果"};
String[] s2={"西瓜","香蕉","蛋糕","苹果","长颈鹿","袋鼠","狗熊","鲸鱼"};
ArrayList a1=new ArrayList();
for(int i=0;i<s2.length;i++){
for(int j=0;j<s1.length;j++){
if(s2[i].equals(s1[j])){
a1.add(s2[i]);
}
}
}
System.out.println(a1);
}
} 再改改
[香蕉, 苹果, 狗熊]