急救，添加数据出错，不难

Question

我使用hibernate自动生成的dao和entity
从from提交的数据也在action中得到
调用dao的save插入数据，可是出现问题BeanUtils.populate
日期我用
方式1 import java.sql.Date;
        student.setBirthday(Date.valueOf(birthday)); 
方式2 import java.util.Date;
       SimpleDateFormat sdf=new SimpleDateFormat ("yyyy-MM-dd"); 
都不行，
查了一下enctype="multipart/form-data"就得不到数据了，还要用上传组件，
也不知道问题处在哪？一直没遇到过，
有没有可能是hibernate或sql server配置问题，
<generator class="identity" />数据库id也是自增的
请各位帮助解决。

Answer 1

dao:public void save(Students transientInstance) {
log.debug("saving Students instance");
try {
getSession().save(transientInstance);
log.debug("save successful");
} catch (RuntimeException re) {
log.error("save failed", re);
throw re;
}
}action:public ActionForward execute(ActionMapping mapping, ActionForm form,
HttpServletRequest request, HttpServletResponse response) {
// TODO Auto-generated method stub
ActionForward forward = mapping.findForward("add");
StudentsDAO studentDao = new StudentsDAO();

String name = request.getParameter("name");
String sex = request.getParameter("sex");
String birth = request.getParameter("birth");
int age = Integer.parseInt(request.getParameter("age"));
String address = request.getParameter("address");
String email = request.getParameter("email");
int tel = Integer.parseInt(request.getParameter("tel"));

SimpleDateFormat sdf=new SimpleDateFormat ("yyyy-MM-dd");
Date Datebirth = null;
try {
Datebirth = sdf.parse(birth);
} catch (ParseException e) {
e.printStackTrace();
} //System.out.println("address.........a.......:"+address);
Students student = new Students();
student.setAge(age);
student.setAddress(address);
student.setEmail(email);
student.setBirth(Datebirth);
student.setName(name);
student.setTel(tel);
student.setSex(sex);
//System.out.println("address.........b.......:"+student.getAddress());
studentDao.save(student);

//System.out.println("address.........c.......:"+address);
return forward;
}

Answer 2

异常堆栈：exception javax.servlet.ServletException: BeanUtils.populate
org.apache.struts.util.RequestUtils.populate(RequestUtils.java:1254)
org.apache.struts.action.RequestProcessor.processPopulate(RequestProcessor.java:821)
org.apache.struts.action.RequestProcessor.process(RequestProcessor.java:254)
org.apache.struts.action.ActionServlet.process(ActionServlet.java:1482)
org.apache.struts.action.ActionServlet.doPost(ActionServlet.java:525)
javax.servlet.http.HttpServlet.service(HttpServlet.java:709)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
org.apache.struts.action.RequestProcessor.doForward(RequestProcessor.java:1069)
org.apache.struts.action.RequestProcessor.processForwardConfig(RequestProcessor.java:455)
org.apache.struts.action.RequestProcessor.process(RequestProcessor.java:279)
org.apache.struts.action.ActionServlet.process(ActionServlet.java:1482)
org.apache.struts.action.ActionServlet.doPost(ActionServlet.java:525)
javax.servlet.http.HttpServlet.service(HttpServlet.java:709)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
root cause java.lang.IllegalArgumentException: argument type mismatch
sun.reflect.NativeMethodAccessorImpl.invoke0(Native Method)
sun.reflect.NativeMethodAccessorImpl.invoke(NativeMethodAccessorImpl.java:39)
sun.reflect.DelegatingMethodAccessorImpl.invoke(DelegatingMethodAccessorImpl.java:25)
java.lang.reflect.Method.invoke(Method.java:585)
org.apache.commons.beanutils.PropertyUtils.setSimpleProperty(PropertyUtils.java:1789)
org.apache.commons.beanutils.PropertyUtils.setNestedProperty(PropertyUtils.java:1684)
org.apache.commons.beanutils.PropertyUtils.setProperty(PropertyUtils.java:1713)
org.apache.commons.beanutils.BeanUtils.setProperty(BeanUtils.java:1019)
org.apache.commons.beanutils.BeanUtils.populate(BeanUtils.java:808)
org.apache.struts.util.RequestUtils.populate(RequestUtils.java:1252)
org.apache.struts.action.RequestProcessor.processPopulate(RequestProcessor.java:821)
org.apache.struts.action.RequestProcessor.process(RequestProcessor.java:254)
org.apache.struts.action.ActionServlet.process(ActionServlet.java:1482)
org.apache.struts.action.ActionServlet.doPost(ActionServlet.java:525)
javax.servlet.http.HttpServlet.service(HttpServlet.java:709)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)
org.apache.struts.action.RequestProcessor.doForward(RequestProcessor.java:1069)
org.apache.struts.action.RequestProcessor.processForwardConfig(RequestProcessor.java:455)
org.apache.struts.action.RequestProcessor.process(RequestProcessor.java:279)
org.apache.struts.action.ActionServlet.process(ActionServlet.java:1482)
org.apache.struts.action.ActionServlet.doPost(ActionServlet.java:525)
javax.servlet.http.HttpServlet.service(HttpServlet.java:709)
javax.servlet.http.HttpServlet.service(HttpServlet.java:802)

Answer 3

页面用的struts标签吧 看看formBean 中的类型与页面上的一致不一致

Answer 4

建议先用一种new Date()试一下，hibernate里date和timestamp是不一样的

Answer 5

页面用的struts标签吧 看看formBean 中的类型与页面上的一致不一致

Answer 6

我也遇到过这种问题，先用new date（）试一下！没用过SQLSERVER不知道它的默认格式是什么样的！

Answer 7

new date（）也不行，怎么办

Answer 8

保存成功了，原来是保存后forward的原因，我想跳转到列表页面，怎么办<action-mappings >
    <action
      attribute="studentForm"
      name="studentForm"
      path="/student"
      scope="request"
      type="com.ldy.struts.action.StudentAction" >
<forward name="list" path="/jsp/list.jsp" />
<forward name="error" path="/jsp/error.jsp" />
</action>
    <action 
     path="/add" 
     type="com.ldy.struts.action.AddAction">
      <forward name="add" path="/student.do" />
    </action>
  </action-mappings>

Answer 9

<action-mappings >
    <action
      attribute="studentForm"
      name="studentForm"
      path="/student"
      scope="request"
      type="com.ldy.struts.action.StudentAction" >
<forward name="list" path="/jsp/list.jsp" />
<forward name="error" path="/jsp/error.jsp" />
</action>
    <action 
     path="/add" 
     type="com.ldy.struts.action.AddAction">
      <forward name="add" path="/student.do" />
    </action>
  </action-mappings>

Answer 10

怎么从一个action通过struts-config.xml,forward到另一个action，继承的action

Answer 11

  <forward
        name="success"
        path="/WEB-INF/success.jsp"
        contextRelative="true" />
      <forward
        name="error"
        path="/error.jsp"
        redirect="true" />

Answer 12

你这是在一个action中，dispatchaction
我继承是action