请问高手如何才能表示出这个100的阶乘啊,好像long型都不够大啊,给我显个0放着啊public class DiGui {
public static long jieCheng(long n){ if(n == 1){
return 1;
}
else{
return n*jieCheng(n-1);
}
}
public static void main(String[] args) {
DiGui d = new DiGui();
System.out.println(d.jieCheng(100));
}}
public static long jieCheng(long n){ if(n == 1){
return 1;
}
else{
return n*jieCheng(n-1);
}
}
public static void main(String[] args) {
DiGui d = new DiGui();
System.out.println(d.jieCheng(100));
}}
public static BigInteger jieCheng(BigInteger n) { if (n.compareTo(new BigInteger("1")) == 0) {
return new BigInteger("1");
} else {
return n.multiply(jieCheng(n.subtract(new BigInteger("1"))));
} } public static void main(String[] args) {
DiGui d = new DiGui();
System.out.println(d.jieCheng(new BigInteger("100")));
}
}用一个BigInteger类就搞定啦
public class XunHuan { public static void main(String[] args) {
BigInteger sum = BigInteger.valueOf(1);
for (int i=1;i<=100;i++){
sum = sum.multiply(BigInteger.valueOf(i));
}
System.out.println(sum);
}}
参加ACM的时候再这么写...平常别这么写...挨老师批~ACM只要求time&mem