JAVA中正则表达式

Question

1.21.33,54.14,54.34
如上字符串我想提取所有数字 但是数字是用,或.分开的而且有数字开头的
本想用两次replaceAll函数
自己的思路是分两次把数字提取出来 补0
如 第一次取只有一个字符4 等补两个0
第二次去34 和54等 补一个0如下
String result="1.21.33,54.4,54.34."
result=result.replaceAll("(\\D)(\\d)(\\D)", "$100$2$3");
result=result.replaceAll("(\\D)(\\d\\d)(\\D)", "$10$2$3");
但是不知道怎么匹配第一个数字1 而且我这么做结果也不正确，请各位前辈指教了

Answer 1

给楼主实现了楼主的功能了。结贴吧
Pattern pattern = Pattern.compile("\\w+[.,]");
                  
                    inputstr = "1.21.33,54.14,54.34.";
                    String t = "0000";
                    String b ="";
                     String[]a = pattern.split(inputstr);
                    matcher = pattern.matcher(inputstr);
                   while(matcher.find())
                   {
                    int start = matcher.start();
                        int end = matcher.end();
                     String s = inputstr.substring(start,end);
                      s = t.substring(0,4 - s.length())+s;
                      b +=s;
                       System.out.println(s);
                   }
               
                 System.out.println(b);

Answer 2

http://community.csdn.net/Expert/TopicView3.asp?id=5597331
都是楼主的帖子，需求差不多，看看我的回帖，两次replaceAll，
没必要每次都靠大家来解决