有谁用过java.util.zip?能用它来任意读写zip文件吗？

Question

比如一个zip文件含有3个文件，要修改第二个文件，行吗？
偶看了看API，好像不行。

Answer 1

/**
TestZip.java
coding by Serol Luo.
[email protected]
2003/07/03
http://www.chinaunix.net/forum/viewforum.php?f=26
转载请保留此信息
*/
import java.util.*;
import java.util.zip.*;
import java.io.*;
class TestZip
{
public void zip(String zipFileName,String inputFile)throws Exception{
zip(zipFileName,new File(inputFile));
}
public void zip(String zipFileName,File inputFile)throws Exception{
ZipOutputStream out=new ZipOutputStream(new FileOutputStream(zipFileName));
zip(out,inputFile,"");
System.out.println("zip done");
out.close();
}public void unzip(String zipFileName,String outputDirectory)throws Exception{
ZipInputStream in=new ZipInputStream(new FileInputStream(zipFileName));
ZipEntry z;
while ((z=in.getNextEntry() )!= null)
{
System.out.println("unziping "+z.getName());
if (z.isDirectory())
{
String name=z.getName();
name=name.substring(0,name.length()-1);
File f=new File(outputDirectory+File.separator+name);
f.mkdir();
System.out.println("mkdir "+outputDirectory+File.separator+name);
}
else{
File f=new File(outputDirectory+File.separator+z.getName());
f.createNewFile();
FileOutputStream out=new FileOutputStream(f);
int b;
while ((b=in.read()) != -1)
out.write(b);
out.close();
}
}in.close();
}public void zip(ZipOutputStream out,File f,String base)throws Exception{
System.out.println("Zipping "+f.getName());
if (f.isDirectory())
{
File[] fl=f.listFiles();
out.putNextEntry(new ZipEntry(base+"/"));
base=base.length()==0?"":base+"/";
for (int i=0;i<fl.length ;i++ )
{
zip(out,fl[i],base+fl[i].getName());
}
}
else
{
out.putNextEntry(new ZipEntry(base));
FileInputStream in=new FileInputStream(f);
int b;
while ((b=in.read()) != -1)
out.write(b);
in.close();
}}
public static void main(String[] args)
{
try{
TestZip t=new TestZip();
t.zip("c:\test.zip","c:\test");
t.unzip("c:\test.zip","c:\test2");
}
catch(Exception e){e.printStackTrace(System.out);}
}
}

Answer 2

一个用java.util.zip创建和读取zip文件的类,供参考

Answer 3

谢谢yexin218！偶另外有办法了