BufferedReader in
= new BufferedReader(new FileReader("foo.in"));
文件foo.in怎么建立?
= new BufferedReader(new FileReader("foo.in"));
文件foo.in怎么建立?
解决方案 »
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然后把名字改成 “foo.in”就ok 了
给分吧
点击"管理",然后给分!!!
BufferedReader in = new BufferedReader(new FileReader(fileName));
File f = new File(args[0]);
BufferedReader in = new BufferedReader(new FileReader(f));in = new BufferedReader
(new InputStreamReader(url.openConnection().getInputStream(),"UTF-8"));
import java.io.*;
import java.util.*;
public class First{
public static void main(String args[])throws IOException,FileNotFoundException{
int a,b,c,d,sum,product;
char ch,tem;
String str;
StringTokenizer tokenizer;
BufferedReader inFile=new BufferedReader(new FileReader("c:\\w.txt"));
PrintWriter outFile=new PrintWriter(new FileWriter("C:\\q.txt"));
tokenizer=new StringTokenizer(inFile.readLine());
a=Integer.parseInt(tokenizer.nextToken());
b=Integer.parseInt(tokenizer.nextToken());
str=tokenizer.nextToken();
tem=str.charAt(0);
c=Integer.parseInt(tokenizer.nextToken());
d=Integer.parseInt(tokenizer.nextToken());
sum=a+b;
product=c*d;
ch=(char)(tem+1);
outFile.println("the sum of "+a+" and "+b+"="+sum );
outFile.println("the character that comes after "+str+" in the Unicode set is "+ch);
outFile.println("the product of "+c+" and "+d+"="+product);
outFile.close();
}
}
Exception in thread "main" java.lang.NumberFormatException:
For input string: "12345"
at java.lang.NumberFormatException.forInputString(NumberFormatException.
java:48)
at java.lang.Integer.parseInt(Integer.java:468)
at java.lang.Integer.parseInt(Integer.java:518)
at First.main(First.java:12)
Press any key to continue...这是怎么回事...