求一个脚本写法

Question

ers[0].addEventListener("mouseover", function(){this.openInfoWindow(infoWindows[0]);});
ers[1].addEventListener("mouseover", function(){this.openInfoWindow(infoWindows[1]);});
ers[2].addEventListener("mouseover", function(){this.openInfoWindow(infoWindows[2]);});
ers[3].addEventListener("mouseover", function(){this.openInfoWindow(infoWindows[3]);});
ers[4].addEventListener("mouseover", function(){this.openInfoWindow(infoWindows[4]);});
ers[5].addEventListener("mouseover", function(){this.openInfoWindow(infoWindows[5]);});
ers[6].addEventListener("mouseover", function(){this.openInfoWindow(infoWindows[6]);});
ers[7].addEventListener("mouseover", function(){this.openInfoWindow(infoWindows[7]);});
ers[8].addEventListener("mouseover", function(){this.openInfoWindow(infoWindows[8]);});
ers[9].addEventListener("mouseover", function(){this.openInfoWindow(infoWindows[9]);});上面的规律写法，我想用一个循环解解决，结果是错误的，求正确写法，谢谢
错误的写法如下
for(i=0;i<ers.length;i++){ers[i].addEventListener("mouseover", function(){this.openInfoWindow(infoWindows[i]);});
}

Answer 1

for(i=0;i<ers.length;i++){
 ers[i].addEventListener("mouseover", (function(i,obj){
  return function(){obj.openInfoWindow(infoWindows[i]); }
 })(i,this) );
}

Answer 2

谢谢二楼。辛苦了。
改了一下：
for(i=0;i<ers.length;i++){
 ers[i].addEventListener("mouseover", (function(i){
  return function(){this.openInfoWindow(infoWindows[i]); }
 })(i) );
}