如何jquery each()方法遍历组成新的数组

通过jquery的$.each（）方法遍历一个对象并取其ID重新拼装成一个数组如何操作？
比如遍历select对象，并取其值：
<select id="test1">
    <option>1</option>
    <option>2</option>
    <option>3</option>
    <option>4</option>
</select>然后拼装成{1,2,3,4}这样的数组，或者json对象

解决方案 »

  1.   

    <!DOCTYPE html PUBLIC "-//W3C//DTD XHTML 1.0 Transitional//EN" "http://www.w3.org/TR/xhtml1/DTD/xhtml1-transitional.dtd">
    <html xmlns="http://www.w3.org/1999/xhtml">
    <head>
    <meta http-equiv="Content-Type" content="text/html; charset=utf-8" />
    <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1.3.2/jquery.min.js"></script>
    <script type="text/javascript">
    var glob_oplist = new Array();
    $(document).ready(function() {
    $('#test1').each(
                                    function() {
                                            $(this).children("option").each(
                                                            function() {
                                                                    glob_oplist.push($(this).text())
                                                            }
                                                    )
                                    }
                            )
                            alert(JSON.stringify(glob_oplist))
    }
    )
    </script>
    </head><body>
    <select id="test1">
      <option>1</option>
      <option>2</option>
      <option>3</option>
    <option>4</option>
    </select></body>
    </html>
      

  2.   

    <script type="text/javascript" src="http://ajax.googleapis.com/ajax/libs/jquery/1/jquery.js"></script>   
    <script>
    $(document).ready(function(){
         var ar=new Array();
           $("#test1").children("option").each(function(){
                ar.push($(this).text());
               
            });
    alert(ar);
    });</script>
    <select id="test1">
      <option>1</option>
      <option>2</option>
      <option>3</option>
      <option>4</option>
    </select>