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Question

  setInterval(function() { Push();  },1000*5);
   function Push() {
alert(456)
   $.ajax({
         type: "POST",
         url: "/enhancement/service_refreshWeb.action",
         dataType: "json",
         success: function(msg){
           alert( "Data Saved: " + msg );
         }
      }); 
      }
不知道哪里出错，方法不走action,

Answer 1

456弹了么？  后面没得分号setInterval(function() { Push();  },1000*5);
改成
setInterval("Push",5000);
或
setInterval("Push()",5000);然后把这句setInterval(function() { Push();  },1000*5); 放在Push函数后面试试

Answer 2

都走方法啦，已经弹出来，就是   $.ajax()里面方法没走

Answer 3

我$.ajax()里面是不是那里写错

Answer 4

$.post("/enhancement/service_refreshWeb.action",
   function(data){
     alert(data);
   }, "json");换个方法试试..

Answer 5

如果是IE代码修改成这样试试
$.ajax({
          type: "POST",
          url: "/enhancement/service_refreshWeb.action",
          dataType: "json",
          success: function(msg){
            alert( "Data Saved: " + msg );
          }
       }),
      } 

Answer 6

刚才修改错了，应该是这样
$.ajax({
           type: "POST",
           url: "/enhancement/service_refreshWeb.action",
           dataType: "json",
           success: function(msg){
             alert( "Data Saved: " + msg );
           }
        },);

Answer 7

我esclipse出问题啦我说怎么不走呢

Answer 8

是缓存了了吧？
 url: "/enhancement/service_refreshWeb.action?t=" + (new Date()).getTime() ,试试