请教大师一段jquery写的Ajax

Question

  function CheckCodeInsert() {
            var code = $("#checkcode").val();
            $.ajax({
                url: "Ajax/CheckCodeInsert.aspx?Code=" + code,
                type: "GET",
                timeout: 30000,
                success: function(data) {
                    if (data == "1") {
                        //                $.ajax({ 
                        //                  url 
                        //                    url: "/Ajax/CheckCodeInsert.aspx?Code=" + code,
                        //                });
                        $("#form1").submit(function() {
                        var uname = $("#test1");
                        var pwd = $("#password1");
                        var Email = $("#email");
                            $.ajax({
                                url: "Ajax/UserRegister.aspx?uname=" + code,
                                type: "GET",
                                timeout: 30000,
                                success: function(data) {
                                }                            });
                        });
                        return true;
                    }
                    else {
                        alert("验证码错误");
                        return false;
                    }
                }
            });        }
      $("#form1").submit(function() {
                        var uname = $("#test1");
                        var pwd = $("#password1");
                        var Email = $("#email");
                            $.ajax({
                                url: "Ajax/UserRegister.aspx?uname=" + code,
                                type: "GET",
                                timeout: 30000,
                                success: function(data) {
                                }                            });问题是点击执行这里的时候,没有反应,是咋回事呢?

Answer 1

function CheckCodeInsert() {
            var code = $("#checkcode").val();
            $.ajax({
                url: "Ajax/CheckCodeInsert.aspx?Code=" + code,
                type: "GET",
                async : false,                success: function(data) {
                 alert(data);//测试                               });        }

Answer 2

   async : false,   
 这个是什么意思

Answer 3

你是要提交表单还是用ajax呢？

Answer 4

 $("#form1").submit(function() { 
                        var uname = $("#test1"); 
                        var pwd = $("#password1"); 
                        var Email = $("#email"); 
                            $.ajax({ 
                                url: "Ajax/UserRegister.aspx?uname=" + code, 
                                type: "GET", 
                                cache: false,//不使用缓存
                                timeout: 30000, 
                                success: function(data) { 
                                }， 
                                error:function(){
                                    alert("访问出错");  //请求失败时调用
                                }
                            });