我写了一个方法,可能写得比较烂,只是希望对你有启发
public ArrayList print()
{
String source = "0123456789";
ArrayList newlist = new ArrayList();
ArrayList oldlist = new ArrayList();
int len = 0;
String s;
//int count=0; while (len < 6)
{
if(oldlist.size()==0)
{
for (int i = 0; i < 5; i++)
newlist.add(source.substring(i,i+1));
}
else
for (int i = 0; i < oldlist.size(); i++)
{
for (int j = 0; j < 10; j++)//此处j初始值可设为oldlist.get(0).toString().length()
{ s = oldlist.get(i).toString();
if ( s.indexOf( source.charAt(j) )<0 &&
s.charAt( s.length()-1 )<source.charAt(j) )
newlist.add(oldlist.get(i).toString() + source.substring(j,j+1));
//count++;
}
}
oldlist.clear();
oldlist.addAll(newlist);
newlist.clear();
len++;
}
//count++;
return oldlist; }
public ArrayList print()
{
String source = "0123456789";
ArrayList newlist = new ArrayList();
ArrayList oldlist = new ArrayList();
int len = 0;
String s;
//int count=0; while (len < 6)
{
if(oldlist.size()==0)
{
for (int i = 0; i < 5; i++)
newlist.add(source.substring(i,i+1));
}
else
for (int i = 0; i < oldlist.size(); i++)
{
for (int j = 0; j < 10; j++)//此处j初始值可设为oldlist.get(0).toString().length()
{ s = oldlist.get(i).toString();
if ( s.indexOf( source.charAt(j) )<0 &&
s.charAt( s.length()-1 )<source.charAt(j) )
newlist.add(oldlist.get(i).toString() + source.substring(j,j+1));
//count++;
}
}
oldlist.clear();
oldlist.addAll(newlist);
newlist.clear();
len++;
}
//count++;
return oldlist; }
解决方案 »
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