例:Test test = new Test();
test.setId("1");
test.setName("zhangsan");
jsonObject.fromobject(test,Test.class).toString;
输出:{"id":"1","name":"zhangsan"}假如不封装name属性,只封装id属性
Test test = new Test();
test.setId("1");
jsonObject.fromobject(test,Test.class).toString;
输出:{"id":"1","name":""}
如果只输出:{"id":"1"}
这样的json字符,有什么方法可以解决么?
test.setId("1");
test.setName("zhangsan");
jsonObject.fromobject(test,Test.class).toString;
输出:{"id":"1","name":"zhangsan"}假如不封装name属性,只封装id属性
Test test = new Test();
test.setId("1");
jsonObject.fromobject(test,Test.class).toString;
输出:{"id":"1","name":""}
如果只输出:{"id":"1"}
这样的json字符,有什么方法可以解决么?
public static void main(String[] args) {
Test t = new Test();
t.id = 10;
JsonConfig jsonConfig = new JsonConfig();
PropertyFilter filter = new PropertyFilter() {
public boolean apply(Object object, String fieldName, Object fieldValue) {
return null == fieldValue;
}
};
jsonConfig.setJsonPropertyFilter(filter);
System.out.println(JSONObject.fromObject(t, jsonConfig).toString());
}
输出为: {"id":10}