分拆列值原著:邹建
改编:爱新觉罗.毓华 2007-12-16 广东深圳有表tb, 如下:
id value
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
欲按id,分拆value列, 分拆后结果如下:
id value
----------- --------
1 aa
1 bb
2 aaa
2 bbb
2 ccc1. 旧的解决方法
SELECT TOP 8000 id = IDENTITY(int, 1, 1) INTO # FROM syscolumns a, syscolumns b SELECT A.id, SUBSTRING(A.[values], B.id, CHARINDEX(',', A.[values] + ',', B.id) - B.id)
FROM tb A, # B
WHERE SUBSTRING(',' + A.[values], B.id, 1) = ','DROP TABLE #2. 新的解决方法 create table tb(id int,value varchar(30))
insert into tb values(1,'aa,bb')
insert into tb values(2,'aaa,bbb,ccc')
go
SELECT A.id, B.value
FROM(
SELECT id, [value] = CONVERT(xml,'<root><v>' + REPLACE([value], ',', '</v><v>') + '</v></root>') FROM tb
)A
OUTER APPLY(
SELECT value = N.v.value('.', 'varchar(100)') FROM A.[value].nodes('/root/v') N(v)
)BDROP TABLE tb/*
id value
----------- ------------------------------
1 aa
1 bb
2 aaa
2 bbb
2 ccc(5 行受影响)
*/
改编:爱新觉罗.毓华 2007-12-16 广东深圳有表tb, 如下:
id value
----------- -----------
1 aa,bb
2 aaa,bbb,ccc
欲按id,分拆value列, 分拆后结果如下:
id value
----------- --------
1 aa
1 bb
2 aaa
2 bbb
2 ccc1. 旧的解决方法
SELECT TOP 8000 id = IDENTITY(int, 1, 1) INTO # FROM syscolumns a, syscolumns b SELECT A.id, SUBSTRING(A.[values], B.id, CHARINDEX(',', A.[values] + ',', B.id) - B.id)
FROM tb A, # B
WHERE SUBSTRING(',' + A.[values], B.id, 1) = ','DROP TABLE #2. 新的解决方法 create table tb(id int,value varchar(30))
insert into tb values(1,'aa,bb')
insert into tb values(2,'aaa,bbb,ccc')
go
SELECT A.id, B.value
FROM(
SELECT id, [value] = CONVERT(xml,'<root><v>' + REPLACE([value], ',', '</v><v>') + '</v></root>') FROM tb
)A
OUTER APPLY(
SELECT value = N.v.value('.', 'varchar(100)') FROM A.[value].nodes('/root/v') N(v)
)BDROP TABLE tb/*
id value
----------- ------------------------------
1 aa
1 bb
2 aaa
2 bbb
2 ccc(5 行受影响)
*/
insert @a select '01.02.03',5.00
union all select '01.02',6.00
union all select '02',7.00 declare @b table(id int identity(1,1),a int)
set rowcount 200
insert @b select 0 from syscolumns a
set rowcount 0
select code,sum(num) num
from
(
select substring(name+'.',id,charindex('.',name+'.',id)-id) code,num
from @a a,@b b
where substring('.'+name,id,1)='.'
)aa
group by code--result
/*code num
--------------------- ----------------------------------------
01 11.00
02 18.00
03 5.00(所影响的行数为 3 行)*/
insert into tb values('第一行:01.02.03',5.00)
insert into tb values('第二行:01.02',6.00)
insert into tb values('第三行:02',7.00)
goSELECT TOP 8000 id = IDENTITY(int, 1, 1) INTO # FROM syscolumns a, syscolumns b SELECT A.num, name = SUBSTRING(substring(A.name,5,len(name)), B.id, CHARINDEX('.', substring(A.name,5,len(name)) + '.', B.id) - B.id)
FROM tb A, # B
WHERE SUBSTRING('.' + substring(A.name,5,len(name)), B.id, 1) = '.'drop table tb,#/*
num name
----------- --------------------------------------------------
5 01
5 02
5 03
6 01
6 02
7 02(所影响的行数为 6 行)
*/
insert into tb values('第一行:01.02.03',5.00)
insert into tb values('第二行:01.02',6.00)
insert into tb values('第三行:02',7.00)
goSELECT TOP 8000 id = IDENTITY(int, 1, 1) INTO # FROM syscolumns a, syscolumns b select name , sum(num) num from
(
SELECT A.num, name = SUBSTRING(substring(A.name,5,len(name)), B.id, CHARINDEX('.', substring(A.name,5,len(name)) + '.', B.id) - B.id)
FROM tb A, # B
WHERE SUBSTRING('.' + substring(A.name,5,len(name)), B.id, 1) = '.'
) t
group by name
order by namedrop table tb,#/*
name num
-------------------------------------------------- -----------
01 11
02 18
03 5(所影响的行数为 3 行)
*/