利用echo $myrow1[xm_name];可以输出项目名称,利用echo $myrow2[zf];可以得到项目的总分,可是如何在php中将其保存在变量中呢?$xm_name=$myrow1[xm_name];和$xm_zf=$myrow2[zf];两句中变量echo后无结果。
$query1=mssql_query("select * from tb_xm where xm_pcid='$xmpc_id'");
while($myrow1=mssql_fetch_assoc($query1)){
echo $myrow1[xm_name];
$xm_name=$myrow1[xm_name];/***************/
$query2=mssql_query("select sum(xmpf_small_zf) as zf from tb_xmpf where xmpf_xm='$myrow1[xm_name]'");
//echo $query2;
echo "总分:";
while($myrow2=mssql_fetch_assoc($query2)){
echo $myrow2[zf];
$xm_zf=$myrow2[zf];
}
$query1=mssql_query("select * from tb_xm where xm_pcid='$xmpc_id'");
while($myrow1=mssql_fetch_assoc($query1)){
echo $myrow1[xm_name];
$xm_name=$myrow1[xm_name];/***************/
$query2=mssql_query("select sum(xmpf_small_zf) as zf from tb_xmpf where xmpf_xm='$myrow1[xm_name]'");
//echo $query2;
echo "总分:";
while($myrow2=mssql_fetch_assoc($query2)){
echo $myrow2[zf];
$xm_zf=$myrow2[zf];
}
系统会报错说Parse error: syntax error, unexpected T_STRING in C:\AppServ\www\online_pf\admin\jgcx_zt_ok.php
$query3=mssql_query("update tb_xm set xm_zf='$myrow2[zf]' where xm_name='$myrow1[xm_name]'");