预设$a=9,执行结果:1 x 1 = 1 1 x 2 = 2 1 x 3 = 3 1 x 4 = 4 1 x 5 = 5 1 x 6 = 6 1 x 7 = 7 1 x 8 = 8 1 x 9 = 9 2 x 1 = 2 2 x 2 = 4 2 x 3 = 6 2 x 4 = 8 2 x 5 = 10 2 x 6 = 12 2 x 7 = 14 2 x 8 = 16 2 x 9 = 18 3 x 1 = 3 3 x 2 = 6 3 x 3 = 9 3 x 4 = 12 3 x 5 = 15 3 x 6 = 18 3 x 7 = 21 3 x 8 = 24 3 x 9 = 27 4 x 1 = 4 4 x 2 = 8 4 x 3 = 12 4 x 4 = 16 4 x 5 = 20 4 x 6 = 24 4 x 7 = 28 4 x 8 = 32 4 x 9 = 36 5 x 1 = 5 5 x 2 = 10 5 x 3 = 15 5 x 4 = 20 5 x 5 = 25 5 x 6 = 30 5 x 7 = 35 5 x 8 = 40 5 x 9 = 45 6 x 1 = 6 6 x 2 = 12 6 x 3 = 18 6 x 4 = 24 6 x 5 = 30 6 x 6 = 36 6 x 7 = 42 6 x 8 = 48 6 x 9 = 54 7 x 1 = 7 7 x 2 = 14 7 x 3 = 21 7 x 4 = 28 7 x 5 = 35 7 x 6 = 42 7 x 7 = 49 7 x 8 = 56 7 x 9 = 63 8 x 1 = 8 8 x 2 = 16 8 x 3 = 24 8 x 4 = 32 8 x 5 = 40 8 x 6 = 48 8 x 7 = 56 8 x 8 = 64 8 x 9 = 72 9 x 1 = 9 9 x 2 = 18 9 x 3 = 27 9 x 4 = 36 9 x 5 = 45 9 x 6 = 54 9 x 7 = 63 9 x 8 = 72 9 x 9 = 81
for($i = 1; $i<= 9; $i++)
{
for($j = 1;$j<= 9; $j++)
{
$f = $i*$j;
echo "$i x $j = $f ";
}
echo '<p>';
}?>我把$a的位置改成9就没有问题~但是我想这个9用网页提交,不知道应该如何处理?
for($i=1;$i<=$a;$i++)
{……
for($i=1;$i<=$_GET['a'];$i++)
{
for($i = 1; $i<= $a; $i++)
{
for($j = 1;$j<= $a; $j++)
{
$f = $i*$j;
echo "$i x $j = $f <br>";
}
echo '<p>';
}?>
1 x 2 = 2
1 x 3 = 3
1 x 4 = 4
1 x 5 = 5
1 x 6 = 6
1 x 7 = 7
1 x 8 = 8
1 x 9 = 9 2 x 1 = 2
2 x 2 = 4
2 x 3 = 6
2 x 4 = 8
2 x 5 = 10
2 x 6 = 12
2 x 7 = 14
2 x 8 = 16
2 x 9 = 18
3 x 1 = 3
3 x 2 = 6
3 x 3 = 9
3 x 4 = 12
3 x 5 = 15
3 x 6 = 18
3 x 7 = 21
3 x 8 = 24
3 x 9 = 27
4 x 1 = 4
4 x 2 = 8
4 x 3 = 12
4 x 4 = 16
4 x 5 = 20
4 x 6 = 24
4 x 7 = 28
4 x 8 = 32
4 x 9 = 36
5 x 1 = 5
5 x 2 = 10
5 x 3 = 15
5 x 4 = 20
5 x 5 = 25
5 x 6 = 30
5 x 7 = 35
5 x 8 = 40
5 x 9 = 45
6 x 1 = 6
6 x 2 = 12
6 x 3 = 18
6 x 4 = 24
6 x 5 = 30
6 x 6 = 36
6 x 7 = 42
6 x 8 = 48
6 x 9 = 54
7 x 1 = 7
7 x 2 = 14
7 x 3 = 21
7 x 4 = 28
7 x 5 = 35
7 x 6 = 42
7 x 7 = 49
7 x 8 = 56
7 x 9 = 63
8 x 1 = 8
8 x 2 = 16
8 x 3 = 24
8 x 4 = 32
8 x 5 = 40
8 x 6 = 48
8 x 7 = 56
8 x 8 = 64
8 x 9 = 72
9 x 1 = 9
9 x 2 = 18
9 x 3 = 27
9 x 4 = 36
9 x 5 = 45
9 x 6 = 54
9 x 7 = 63
9 x 8 = 72
9 x 9 = 81
那么程序这样写:
<?php
for($i=1;$i<=$_GET['a'];$i++)
{$_GET['a']的值就是9
<?
for($i=1;$i<=$_GET['a'];$i++)
{
for($i=1;$i<=$_GET['a'];$i++)
{
$f = $i*$j;
echo "$i x $j = $f <br>";
}
echo '<p>';
}?>输出1 x = 0
2 x = 0
3 x = 0
4 x = 0
5 x = 0
6 x = 0
7 x = 0
8 x = 0
9 x = 0
错误了吧?
{
for($i=1;$i<=$_GET['a'];$i++)
{两个循环都是$i?
代码的测试结果给你了,怎样取得$a的值给你了,for()的用法也给你了,哪里有错误也给你了,我也该睡了。再奉劝你一句:看看手册里关于“for()”的用法,明确一下何时循环会终止。
for($i = 1; $i<= $a; $i++)
你自己已经写了#a=0,$i = 1
那么循环条件$i<= $a 怎么可能会成立呢?
$a = $_GET['a'];
for($i = 1; $i<= $a; $i++)
{
for($j = 1;$j<= $a; $j++)
{
$f = $i*$j;echo "$i x $j = $f <br/>";
}
echo '<p>';
}
?>
$a = $_GET['a'];然后你那边的表单这样提交就可以了:index.php?$a=9
index.php?$a=9 应该是 index.php?a=9
for($i = 1; $i<= $a; $i++) //或者把上面去掉,把这里和下面的$a换成$_GET['a']
{
for($j = 1;$j<= $a; $j++)
{
$f = $i*$j;echo "$i x $j = $f <br/>";
}
echo '<p>';
}?>两个FOR 里面一个是$i,一个是$j,不要搞错了
最后说一句,楼主已经进入无敌模式了 DEBUG OFF ^_^