有关ip地址的函数，返回值老是空的

Question

$ip = !empty($_SERVER['HTTP_CLIENT_IP']) ? 
      $_SERVER['HTTP_CLIENT_IP'] : 
      (  !empty($_SERVER['HTTP_X_FORWARDED_FOR']) ? 
         $_SERVER['HTTP_X_FORWARDED_FOR'] : 
         $_SERVER['REMOTE_ADDR']
      );

Answer 1

function getip()
{
return !empty($_SERVER['HTTP_CLIENT_IP']) ? $_SERVER['HTTP_CLIENT_IP'] : (!empty($_SERVER['HTTP_X_FORWARDED_FOR']) ? $_SERVER['HTTP_X_FORWARDED_FOR'] : $_SERVER['REMOTE_ADDR']);
}

Answer 2

hehe。楼主可以用楼上方法，或者在最开始加上一句extract($_SERVER);来看看。

Answer 3

if( getenv('HTTP_X_FORWARDED_FOR') != '' )
{
$client_ip = ( !empty($_SERVER['REMOTE_ADDR']) ) ? $_SERVER['REMOTE_ADDR'] : ( ( !empty($_ENV['REMOTE_ADDR']) ) ? $_ENV['REMOTE_ADDR'] : $REMOTE_ADDR ); $entries = explode(',', getenv('HTTP_X_FORWARDED_FOR'));
reset($entries);
while (list(, $entry) = each($entries)) 
{
$entry = trim($entry);
if ( preg_match("/^([0-9]+\.[0-9]+\.[0-9]+\.[0-9]+)/", $entry, $ip_list) )
{
$private_ip = array('/^0\./', '/^127\.0\.0\.1/', '/^192\.168\..*/', '/^172\.((1[6-9])|(2[0-9])|(3[0-1]))\..*/', '/^10\..*/', '/^224\..*/', '/^240\..*/');
$found_ip = preg_replace($private_ip, $client_ip, $ip_list[1]); if ($client_ip != $found_ip)
{
$client_ip = $found_ip;
break;
}
}
}
}
else
{
$client_ip = ( !empty($_SERVER['REMOTE_ADDR']) ) ? $_SERVER['REMOTE_ADDR'] : ( ( !empty($_ENV['REMOTE_ADDR']) ) ? $_ENV['REMOTE_ADDR'] : $REMOTE_ADDR );
}