怎么让内容 横向排列

Question

在循环外先定义个$i
$i = 1;
while ($row = mysql_fetch_array($query)){
   if ($i%3 != 0)
      echo $row['field']." ";
   else
      echo $row['field']."<br>";
   $i++;
}

Answer 1

<?php
            include_once "./manage/connect.php";
            $query_s="select atid,atname,atparent from article_type where atparent='0'";
           
           $i = 1;
while ($row = mysql_fetch_array($query)){
   if ($i%3 != 0)
      echo $row['field']."&nbsp;";
   else
      echo $row['field']."<br>";
   $i++;
}            echo "
<table align='top'   border='0' cellspacing='0' cellpadding='0' align='center'>
<tr>
            
  <td  class='a12b' >&nbsp;{$row_s[atname]}</td></tr>
</table>
";
           
            }
            ?>这样写对不对 怎么不显示 错在哪里

Answer 2

该过之后 
 <?php
            include_once "./manage/connect.php";
            $query_s="select atid,atname,atparent from article_type where atparent='0'";
           
         $i = 1;
while ($row = mysql_fetch_array($query)){
   if ($i%3 != 0)
      echo $row['atname']."&nbsp;";
   else
      echo $row['atname']."<br>";
   $i++;
}            
            ?>不显示

Answer 3

你上面的是$query_s,我那里写的是$query
当然不会显示拉

Answer 4

<?php
   include_once "./manage/connect.php";
   $query_s="select atid,atname,atparent from article_type where atparent='0'";
   $i = 1; 
   while ($row = mysql_fetch_array($query_s)){
      if ($i%3 != 0)
          echo $row['field']."&nbsp;";
       else
          echo $row['field']."<br>";
      $i++;
    }
    echo "
      <table align='top'   border='0' cellspacing='0' cellpadding='0' align='center'>
         <tr>
             <td  class='a12b' >
               <?php echo $row_s[atname]?>
             </td>
        </tr>
    </table>
   ";   ?>