dim pic:pic = Array("1.gif","2.gif","3.gif","4.gif","5.gif","6.gif","7.gif","8.gif","9.gif","10.gif","11.gif","12.gif","13.gif","14.gif","15.gif")
dim channelID
channelID = Request.QueryString("channelID")
Response.Write "<img src="&pic(channelID-1)&">"

解决方案 »

  1.   

    不好意思,前面两个板块一起在看
    <?php
    $pic = array("1.gif","2.gif","3.gif","4.gif","5.gif","6.gif","7.gif","8.gif","9.gif","10.gif","11.gif","12.gif","13.gif","14.gif","15.gif");
    $channelID = $_GET['channelID'];
    echo "<img src=".$pic[$channelID-1].">";
    ?>
      

  2.   

    请问中间$channelID 是什么意思,我对数组不太熟悉
      

  3.   

    查询串channelID的结果,这里自己改,看你的程序是如何获得栏目号的
      

  4.   

    还有我是从外部url得到栏目的,比如photo-1 对应p1.gif ,以此类推,该怎么写