php preg_replace

Question

本帖最后由 sujunlin_1987 于 2010-03-19 20:43:51 编辑

Answer 1

<?
while($rs=mysql_fetch_array($result)){
$NerworkName=$rs["NerworkName"];
if (is_array($search_array)){
    $search_array=implode("|",$search_array);
}
$NerworkName=preg_replace("/($search_array)/i","<font style='color:#aa1234'>\\1</font>",$NerworkName);
?>
    <div id="x_<?=$rs["ID"]?>" class="list_main">
        <div class="list"><?=$NerworkName?></div>
    </div>    
<?
}
?>

Answer 2

 $NerworkName=preg_replace("/($search_array[$i])/i","<font style='color:#aa1234'>\\1</font>",$NerworkName);这句有问题! 不知道怎么改
如果我搜索的是 "1 2"内容会错乱 原因是'color:#aa1234'
如果输入"1"或不包含aa1234的字母或数字 就没问题!数据库数据:123123
搜索"1" 结果为<font style='color:#aa1234'>1</font>23<font style='color:#aa1234'>1</font>23
搜索"1 2" 结果为234'>1<font style='color:#aa1234'>2</font>3234'>1<font style='color:#aa1234'>2</font>3

Answer 3

 $NerworkName=preg_replace("/($search_array[$i])/i","<font style='color:#aa1234'>\\1</font>",$NerworkName);数据库数据:789789
搜索"7 8 9" 结果正确数据库数据:123123
搜索"1 2 3" 结果错误

Answer 4

试了和我原先效果一样!
错误应该是在这句
 $NerworkName=preg_replace("/($search_array[$i])/i","<font style='color:#aa1234'>\\1</font>",$NerworkName);

Answer 5

<?
$NerworkName="1245367890abcdefghi";
$search_array=array(1,2,3);
if (is_array($search_array)){
    $search_array=implode("|",$search_array);
}
$NerworkName=preg_replace("/($search_array)/i","<font style='color:#aa1234'>\\1</font>",$NerworkName);
echo $NerworkName."<br>";//1245367890abcdefghi 1、2、3都是有色的
echo htmlspecialchars($NerworkName);//<font style='color:#aa1234'>1</font><font style='color:#aa1234'>2</font>45<font style='color:#aa1234'>3</font>67890abcdefghi
?>

Answer 6

我也是碰到类似问题；date='$cur_user=33011011';
    echo $date.'<br />';
    echo $dat=preg_replace("/^[1-9]{2}[0-1][0-9]{3}[1][1-3]$/","33000111",$date);
这个替换不了