PHP文件路径问题

Question

从后台上传图片，用getcwd（）得到文件路径，如"E:/SOURCE/SERVICE/UPLOADIMAGE",但是存入数据库后就变成"E:SOURCESERVIECEUPLOADIMAGE",中间的/没了，导致取不出正确的路径，哪位大神可以帮忙解决一下问题啊
$upload_dir = getcwd();
$newfilename = makefilename();
$oldfilename = $_FILES['upfile']['name']; // 服务器端临时文件名
$pos = strrpos($oldfilename, '.'); // 获取文件名中最右侧的.
$ext = substr($oldfilename, $pos, strlen($oldfilename)-$pos); // 获取文件的扩展名
$newspic = $upload_dir. $newfilename . $ext;
$up_name=$_FILES['upfile']['name'];//客户端文件名
代码如上，需要存入数据库的为$newspic

Answer 1

if($newsid!=0){
      $in_sql="insert into                          upfile(newsid,upfilename,up_name,upfiledis,upfileurl,uptime,new_upfilename)values('$newsid','$upfilename','$up_name','$upfiledis','$upfileurl','$uptime','$newfilename') ";
 
 if(mysql_query($in_sql)){  
    ?>     
    <script>alert('恭喜您，添加成功！');window.location='new_display.php?typeid=<?php echo $typeid?>&borderid=<?php echo $borderid?>';    </script>";
    <?PHP
     }else{
?>
          <script>alert('很抱歉，添加失败！');window.location='new_display.php?typeid=<?php echo $typeid?>&borderid=<?php echo $borderid?>';  

Answer 2

错了，是这个 $in_sql="insert into news(typeid,borderid,topic,n_key,writer,ntime,content,count,newspic)values('$typeid','$borderid','$topic','$n_key','$writer','$ntime','$content','0','$newspic') ";  if(mysql_query($in_sql)){  
?>     
    <script>alert('恭喜您，添加成功！');window.location='new_display.php?typeid=<?php echo $typeid?>&borderid=<?php echo $borderid?>';    </script>";
    <?PHP
     }else{
?>
         <script>alert('很抱歉，添加失败！');window.location='new_display.php?typeid=<?php echo $typeid?>&borderid=<?php echo $borderid?>';         </script>";

Answer 3

用addslashes()注意php 5.3 前后版本会有点区别，查看手册magic_quotes_gpc及相关说明，考虑兼容性 

Answer 4

$upload_dir = addslashes(getcwd()).'\\';