<script type="text/javascript">
imgUrl1="up/01.jpg";
imgtext1="标题01"
imgLink1=escape("openAccount.php")
imgUrl2="up/02.jpg";
imgtext2="标题02"
imgLink2=escape("openAccount.php");
imgUrl3="up/03.jpg";
imgtext3="标题03"
imgLink3=escape("openAccount.php");
imgUrl4="up/04.jpg";
imgtext4="标题04"
imgLink4=escape("openAccount.php");
imgUrl5="up/05.jpg";
imgtext5="标题05"
imgLink5=escape("openAccount.php");
我现在有个PHP的变量$title1,怎样将它赋在js的变量imgtext1上面呢?

解决方案 »

  1.   

    <script type="text/javascript">
    imgUrl1="up/01.jpg";
    imgtext1="<?php echo $title1;?>"
    imgLink1=escape("openAccount.php")
    imgUrl2="up/02.jpg";
    imgtext2="标题02"
    imgLink2=escape("openAccount.php");
    imgUrl3="up/03.jpg";
    imgtext3="标题03"
    imgLink3=escape("openAccount.php");
    imgUrl4="up/04.jpg";
    imgtext4="标题04"
    imgLink4=escape("openAccount.php");
    imgUrl5="up/05.jpg";
    imgtext5="标题05"
    imgLink5=escape("openAccount.php");
      

  2.   

    LZ可以这样
    <input type="hidden" name="myphp" id="myphp" value="<?php echo $title1;?>"><script type="text/javascript">
    imgUrl1="up/01.jpg";
    //imgtext1="标题01"
    imgtext1=document.getElementById("myphp").value;
    imgLink1=escape("openAccount.php")
    imgUrl2="up/02.jpg";
    imgtext2="标题02"
    imgLink2=escape("openAccount.php");
    imgUrl3="up/03.jpg";
    imgtext3="标题03"
    imgLink3=escape("openAccount.php");
    imgUrl4="up/04.jpg";
    imgtext4="标题04"
    imgLink4=escape("openAccount.php");
    imgUrl5="up/05.jpg";
    imgtext5="标题05"
    imgLink5=escape("openAccount.php");
      

  3.   

    <script type="text/javascript"> 
    var title = "<?=$title?>";
    //var title = "<?php echo $title;?>";
    </script>
    两种都可以的.
      

  4.   

    js.php<!-- 方法1 -->
    <?php 
    #输出应满足javascript语法,对于输出字符串应当注意转义字符
    $return=$_GET['return'];
    $var=$_GET['var'];
    $array=array("name"=>"mengdejun","age"=>22,"address"=>"hubei province","qq"=>280759843,"desc"=>"js call php");
    $json=json_encode($array);
    echo "function add(a,b){return a+b}";
    echo "var $return=$json;";
    echo "var $var='http://hi.baidu.com/mak00000';";
    ?>
    <!-- 方法2 -->
    function show()
    {
    alert('mengdejun');
    }js.html<script type="text/javascript" src='js.php?return=ps&var=url'></script>
    <script type="text/javascript">
    document.write(ps.name+"<br/>"+ps.age+"<br/>"+ps.qq+"<br/>"+ps.desc);
    document.write("<br/>12+12="+add(12,12));
    document.write("<br/><a href='"+url+"'>js调用php变量,另外一种ajax实现</a>");
    show();
    </script>
    更多信息参考:http://hi.baidu.com/mak0000/blog/item/fd9e4bdd272c78b1cd116686.html