菜鸟问题：退出问题

Question

<script language=javascript>
  window.parent.location.href = index.php; 
</script>

Answer 1

logout.php
<?phpsession_start(); 
session_destroy(); 
header("location:login.php?action=logout");?>

Answer 2

<script language=javascript>
  window.parent.location.href = index.php; 
</script>这样用action=logout怎么传递？

Answer 3

<script language=javascript>
  window.parent.location.href = 'index.php?action=logout'; 
</script>这样用action=logout怎么传递？

Answer 4

<?phpsession_start(); 
session_destroy(); 
echo "<script>window.open('login.php?action=logout','_top');</script>";?>

Answer 5

top.html
<a href="javascript:Logout()">退出</a>
logout.php
<?php
@session_destroy();
header("Location:'login.php?action=logout'");?>

Answer 6

<a herf="#" target=""></a> 方法在target中 好象是_TOP 嘿嘿 就那么几个试试就知道了

Answer 7

<script>
function Logout(){
top.location = 'logout.php';
}
</script>忘了要在top.html 加上上面的js。

Answer 8

top.html
<a href="http://localhost/logout.php">退 出</a>logout.php
<?phpsession_start(); 
session_destroy(); 
echo "<script>window.parent.location.href='login.php?action=logout';</script>";?>晕,上次给你提示了呀,这样就可以了.

Answer 9

echo "<script>location.href='login.php?action=logout';</script>";
是的啊
你上面的那句话就是打开登陆界面的啊
echo "<script>window.location='login.php?action=logout';</script>";
试试

Answer 10

top.html
<a href="http://localhost/logout.php" target="_parent">退 出</a>logout.php
<?phpsession_start(); 
session_destroy(); 
echo "<script>location.href='login.php?action=logout';</script>";?>

Answer 11

<a href="http://localhost/logout.php">退 出</a>
少了一个_target，<a href="http://localhost/logout.php" _target="****">退 出</a>
****为你框架的名称。