ecshop 后台分页报parseResult() error: can't parse toJSON. 错误怎么解决

Question

各位大神 问下 ecshop后台分页 点下一页报 uncaught exception: transport.js/parseResult() error: can't parse to JSON.  错误怎么解决

Answer 1

既然是 无法解析JSON
那就是你返回的数据错了！
那么你返回了什么呢？

Answer 2

可以贴一下parseResult（） 方法的代码出来看看。

Answer 3

 /* *
  * 对返回的结果进行格式化。
  *
  * @private
  * @return 返回特定格式的数据结果
  * @type mix
  */
  parseResult : function (responseType, xhr)
  {
    var result = null;    switch (responseType)
    {
      case "JSON" :
        result = this.preFilter(xhr.responseText);
        try
        {
          result = $.evalJSON(result);
        }
        catch (ex)
        {
          throw this.filename + "/parseResult() error: can't parse to JSON.\n\n" + xhr.responseText;
        }
        break;
      case "XML" :
        result = xhr.responseXML;
        break;
      case "TEXT" :
        result = this.preFilter(xhr.responseText);
        break;
      default :
        throw this.filename + "/parseResult() error: unknown response type:" + responseType;
    }
我也报同样的错，有大侠能指点下吗？

Answer 4

打开页面时的报错信息：
Uncaught transport.js/parseResult() error: can't parse to JSON.{"error":0,"message":"","content":"","new_orders":"0","new_paid":"0"} transport.js:412
翻页时的报错信息：
Uncaught transport.js/parseResult() error: can't parse to JSON.{"error":0,"message":"","content":null,"filter":{"cat_id":0,"intro_type":"","is_promote":0,"stock_warning":0,"brand_id":0,"keyword":"","suppliers_id":"","is_on_sale":"","sort_by":"goods_id","sort_order":"DESC","extension_code":"","is_delete":0,"real_goods":1,"supp":0,"record_count":"107","page_size":15,"page":4,"page_count":8,"start":45},"page_count":8} 

Answer 5

JSON没问题