$.ajax({
url: "../common/toSession.php",
type:"post",
dataType:"text/html",
data: "123", error:function(msg){
alert("ajax请求失败"); }
,
success:function(msg){
alert("it's ok");}
});
我无法使用ajax 为啥? 是不是需要插件之类的? 老是出来ajax请求失败
url: "../common/toSession.php",
type:"post",
dataType:"text/html",
data: "123", error:function(msg){
alert("ajax请求失败"); }
,
success:function(msg){
alert("it's ok");}
});
我无法使用ajax 为啥? 是不是需要插件之类的? 老是出来ajax请求失败
请求失败 看看你请求的地址有没有错误.
而tosession.php的路径是D:\xampp\htdocs\ARTools\common\tosession.php
<?php session_start();
$myquery =$_POST['query'];
$_SESSION['query2'] = $myquery;?>
<?php session_start();
$myquery =$_POST['data'];
$_SESSION['query2'] = $myquery;?>
url: "toSession.php",一定要写成相对路径的形式,那要写作
url: "../toSession.php",
或
url: "../../common/toSession.php",
$.ajax({
url: "../common/toSession.php",
type:"post",
dataType:"text/html",
data: "data=123", error:function(msg){
alert("ajax请求失败"); }
,
success:function(msg){
alert("it's ok");}
});
123=123 | key=value
前面是 $_POST['123'].
还有就是data: "data=123", 如果我想把123换成名为mysqlcri的sql字符串咋弄啊
url: "../common/toSession.php",问题1:这儿路径可能有问题
type:"post",
dataType:"text/html",
data: "123", error:function(msg){ 问题2:这儿没有键值,反正我没用过这样光秃秃的
alert("ajax请求失败"); }
,
success:function(msg){
alert("it's ok");}
});
这句去掉试试