关于CreateFileMapping和OpenFileMapping

Question

新人求教：
我在一个程序中写到： hMemSrv = CreateFileMapping((HANDLE)0xFFFFFFFF,NULL,PAGE_READWRITE,0,300,"MNCTC"); 
我在另一个程序中写：    hMemGUI = OpenFileMapping(FILE_MAP_READ,FALSE, "MNCTC");这样能达到共享内存么？

Answer 1

one:set
#include <iostream.h>
#include <stdio.h>
#include <windows.h>int main()
{
HANDLE hMemSrv;
unsigned char *pSetBuf;
hMemSrv = CreateFileMapping((HANDLE)0xFFFFFFFF,NULL,PAGE_READWRITE,0,300,"MNCTC"); 
pSetBuf = (unsigned char *)MapViewOfFile(hMemSrv, FILE_MAP_WRITE,0,0,300);
char *ch = (char *)pSetBuf; ch[4] = 'p'; int b;
cin>>b;
UnmapViewOfFile(pSetBuf);
CloseHandle(hMemSrv); return 1;
}two:get
#include <iostream.h>
#include <stdio.h>
#include <windows.h>int main()
{ HANDLE hMemGUI;
unsigned char *pGetBuf;
(1)// hMemGUI = OpenFileMapping(FILE_MAP_READ,FALSE, "MNCTC");
(2)// hMemGUI = CreateFileMapping((HANDLE)0xFFFFFFFF,NULL,PAGE_READWRITE,0,300,"MNCTC"); 
pGetBuf = (unsigned char *)MapViewOfFile(hMemGUI, FILE_MAP_WRITE,0,0,300);
 
cout<<pGetBuf[4]<<endl;

int d;
cin>>d; UnmapViewOfFile(pSetBuf);
CloseHandle(hMemSrv); return 1;
}用语句1可以读出p
用语句2报.exe错误。请问怎么回事？

Answer 2

  google 内存映射文件