WIN API waveOut双缓冲如何实现

Question

程序很简单，就是把一段很长的音频，分成一秒的片段处理然后播放，用单缓冲会出现咔咔的声音，就想使用双缓冲，结果咔咔声并没有消除，而且播放音频很乱，简单代码如下：UNI_SZ= 44100;
HWAVEOUT hwaveout;
WAVEFORMATEX waveformat;
waveformat.wFormatTag      = WAVE_FORMAT_PCM ;
waveformat.nChannels       = 2 ;
waveformat.nSamplesPerSec  = 44100 ;
waveformat.nAvgBytesPerSec = waveformat.nSamplesPerSec*2*2 ;
waveformat.nBlockAlign     = 4 ;
waveformat.wBitsPerSample  = 16 ;
waveformat.cbSize          = 0 ;waveOutOpen(&hwaveout,WAVE_MAPPER,&waveformat,(DWORD)waveOutProc,NULL,CALLBACK_FUNCTION );
short* pSht=(short*)calloc(sizeof(short)*UNI_SZ*2,1);
short* pSht1=(short*)calloc(sizeof(short)*UNI_SZ*2,1);PWAVEHDR waveheadr=(PWAVEHDR)calloc(1,sizeof(WAVEHDR));
waveheadr->lpData=(char*)pSht;
waveheadr->dwBytesRecorded=0;
waveheadr->dwLoops=1;PWAVEHDR waveheadr1=(PWAVEHDR)calloc(1,sizeof(WAVEHDR));
waveheadr1->lpData=(char*)pSht1;
waveheadr1->dwBytesRecorded=0;
waveheadr1->dwLoops=1;bool llll=true;
while（...）
{
    short Out[UNI_SZ+200]={0};
    process(...);
    if(llll)
    {
for (int ijk=0;ijk<current_block_size;ijk++)
{
pSht[ijk]=lOut[ijk];

}

llll=false;
     }
    else
    {
        for (int ijk=0;ijk<current_block_size;ijk++)
        {
               pSht1[ijk]=Out[ijk];
        }        llll=true;
    }
waveOutPrepareHeader(hwaveout,waveheadr,sizeof(WAVEHDR));
waveOutPrepareHeader(hwaveout,waveheadr1,sizeof(WAVEHDR));

waveOutWrite(hwaveout,waveheadr,sizeof(WAVEHDR));
waveOutWrite(hwaveout,waveheadr1,sizeof(WAVEHDR));
}
waveOutClose(hwaveout);回调函数如下：
void CALLBACK waveOutProc(
HWAVEOUT hwo,      
UINT uMsg,         
DWORD dwInstance,  
DWORD dwParam1,    
DWORD dwParam2     
)
{
//HANDLE hEvt=(HANDLE)dwInstance;
if(uMsg == WOM_DONE)
{ 
LPWAVEHDR pWaveHeader = (LPWAVEHDR)dwParam1;//系统自动识别是哪一个WAVEHDR播放完毕

waveOutUnprepareHeader( hwo, pWaveHeader, sizeof(WAVEHDR) );//播放完后须调用此函数

//此处填充WAVEHDR的lpdate缓冲

waveOutPrepareHeader( hwo, pWaveHeader, sizeof(WAVEHDR));
waveOutWrite( hwo, pWaveHeader, sizeof(WAVEHDR) ); }
return;
}

Answer 1

\Windows程序设计Code\Chap22\Record1\Record1.c
BOOL MakeWaveFile (INS ins, TCHAR * szFileName)
{
     DWORD        dwWritten ;
     HANDLE       hFile ;
     int          iChunkSize, iPcmSize, iNumSamples ;
     PBYTE        pBuffer ;
     WAVEFORMATEX waveform ;     hFile = CreateFile (szFileName, GENERIC_WRITE, 0, NULL,
                         CREATE_ALWAYS, FILE_ATTRIBUTE_NORMAL, NULL) ;
 
     if (hFile == NULL)
          return FALSE ;
     
     iNumSamples = ((long) ins.iMsecTime * SAMPLE_RATE / 1000 + 1) / 2 * 2 ;
     iPcmSize    = sizeof (PCMWAVEFORMAT) ;
     iChunkSize  = 12 + iPcmSize + 8 + iNumSamples ;
     
     if (NULL == (pBuffer = malloc (iNumSamples)))
     {
          CloseHandle (hFile) ;
          return FALSE ;
     }
     
     FillBuffer (ins, pBuffer, iNumSamples) ;
     
     waveform.wFormatTag      = WAVE_FORMAT_PCM ;
     waveform.nChannels       = 1 ;
     waveform.nSamplesPerSec  = SAMPLE_RATE ;
     waveform.nAvgBytesPerSec = SAMPLE_RATE ;
     waveform.nBlockAlign     = 1 ;
     waveform.wBitsPerSample  = 8 ;
     waveform.cbSize          = 0 ;
     
     WriteFile (hFile, "RIFF",       4, &dwWritten, NULL) ;
     WriteFile (hFile, &iChunkSize,  4, &dwWritten, NULL) ;
     WriteFile (hFile, "WAVEfmt ",   8, &dwWritten, NULL) ;
     WriteFile (hFile, &iPcmSize,    4, &dwWritten, NULL) ;
     WriteFile (hFile, &waveform, sizeof (WAVEFORMATEX) - 2, &dwWritten, NULL) ;
     WriteFile (hFile, "data",       4, &dwWritten, NULL) ;
     WriteFile (hFile, &iNumSamples, 4, &dwWritten, NULL) ;
     WriteFile (hFile, pBuffer,      iNumSamples,  &dwWritten, NULL) ;
     
     CloseHandle (hFile) ;
     free (pBuffer) ;
     
     if ((int) dwWritten != iNumSamples)
     {
          DeleteFile (szFileName) ;
          return FALSE ;
     }
     return TRUE ;
}

Answer 2

http://download.csdn.net/source/3184342