关于蓝牙socket 服务器端首次accept总出错！

Question

做个循环，当错误时重新执行过，直到无错误后退出循环，这个应该是UUID识别的问题。

Answer 1

楼上的我试了一下，还是不太行……我在错误信息中发现如下行报错 @Override
    public void onStart() {
        super.onStart();
 
        //启动服务器的线程
        if (mAcceptThread == null) {
           //点击打印出的错误信息，光标会移动到这里
            mAcceptThread = new AcceptThread();            
           mAcceptThread.start();       
        }
    }    public Handler getHandler(){   
       return this.handler;
    }    private class AcceptThread extends Thread {
       private final BluetoothServerSocket mmServerSocket;
       private InputStream mmInStream;
 
       public AcceptThread() {
           final String SPP_UUID = "00001101-0000-1000-8000-00805F9B34FB";   
           UUID uuid = UUID.fromString(SPP_UUID); 
           BluetoothServerSocket tmp = null;
           
           try {
           tmp = mBluetoothAdapter.listenUsingRfcommWithServiceRecord(Name,uuid);
           } catch (IOException e) { 
                   //这里报出异常
            System.out.println("Rfcomm出错");            e.printStackTrace();
           }
           mmServerSocket = tmp;
       }       public void run() {
           BluetoothSocket socket = null;
        
           // Keep listening until exception occurs or a socket is returned
           while (true) {
               try {
                System.out.println(mmServerSocket);
                   socket = mmServerSocket.accept();
               } catch (IOException e) {
                e.printStackTrace();
                finish();
                   break;
           }
            // If a connection was accepted
            if (socket != null) {
                try {
                 怎么解决呢 各位大牛们！

Answer 2

我换了种写法就参考网上说的
发送端
//建立socket连接
               BluetoothSocket tmp = null;
               mdevice = device;
               try {
                   Method m = mdevice.getClass().getMethod("createRfcommSocket", new Class[]{int.class});
               try{                   tmp = (BluetoothSocket)m.invoke(mdevice, Integer.valueOf(29));               }catch(Exception e){
                System.out.println("Exception111");
                e.printStackTrace();
               }               }catch(NoSuchMethodException e){
                System.out.println("NoSuchMethodException");
                e.printStackTrace();
               }
                  msocket = tmp;接收端
   Method listenMethod = null;
try {
listenMethod = mBluetoothAdapter.getClass().getMethod("listenUsingRfcommOn", new Class[]{int.class});
} catch (SecurityException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (NoSuchMethodException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
           try {
tmp = ( BluetoothServerSocket) listenMethod.invoke(mBluetoothAdapter, new Object[]{ 29});
} catch (IllegalArgumentException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (IllegalAccessException e) {
// TODO Auto-generated catch block
e.printStackTrace();
} catch (InvocationTargetException e) {
// TODO Auto-generated catch block
e.printStackTrace();
}
           mmServerSocket = tmp;结果就好了

Answer 3

这句话中( BluetoothServerSocket) listenMethod.invoke(mBluetoothAdapter, new Object[]{ 29});
最后29代表啥呀？？没弄懂求大神指导一下