一个有关Content Provider的问题

Question

2.0及以上要用
long id = cursor.getLong(cursor.getColumnIndex("_id"));
Cursor pcur = getContentResolver().query(
ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
null,
ContactsContract.CommonDataKinds.Phone.CONTACT_ID + "="
+ Long.toString(id), null, null);
 
// 处理多个号码的情况
String phoneNumbers = "";
while (pcur.moveToNext()) {
String strPhoneNumber = pcur
.getString(pcur
.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
if(phoneNumbers==null||phoneNumbers.trim().length()==0){
phoneNumbers += strPhoneNumber;
}else{
phoneNumbers += strPhoneNumber + ":";
}
}
pcur.close();

Answer 1

provider好像必须有一个_id的字段，你可以用xxx as _id

Answer 2

listData = new ArrayList<Map<String, Object>>();
 
// read contacts
Cursor cur = getContentResolver().query(
ContactsContract.Contacts.CONTENT_URI, null, null, null, null);
startManagingCursor(cur);
 
while (cur.moveToNext()) {
Map<String, Object> mp = new HashMap<String, Object>();
 
long id = cur.getLong(cur.getColumnIndex("_id"));
Cursor pcur = getContentResolver().query(
ContactsContract.CommonDataKinds.Phone.CONTENT_URI,
null,
ContactsContract.CommonDataKinds.Phone.CONTACT_ID + "="
+ Long.toString(id), null, null);
 
// 处理多个号码的情况
String phoneNumbers = "";
while (pcur.moveToNext()) {
String strPhoneNumber = pcur
.getString(pcur
.getColumnIndex(ContactsContract.CommonDataKinds.Phone.NUMBER));
if(phoneNumbers==null||phoneNumbers.trim().length()==0){
phoneNumbers += strPhoneNumber;
}else{
phoneNumbers += strPhoneNumber + ":";
}
}
pcur.close();

String name = cur.getString(cur.getColumnIndex("display_name"));
mp.put(NAME, name);
mp.put(NUMBER, phoneNumbers);
mp.put("check", "0");
listData.add(mp);
}
cur.close();