请教高手，sax解析xml遇到&amp如何解析

 请教高手，sax解析xml遇到&amp如何解析，如下面这一条
<menulink>http://www.submenu.jsp?mn=gx&amp;ps=9</menulink> 
使用语句            if(currentElementName.equals("menulink")&&textContent!=null&&!textContent.trim().equals("")){  
                Log.i("textContent age", textContent);  
                beauty.setMenulink(textContent);但是，得出的值是这样的
12-06 07:46:43.298: INFO/currentElementName(831): menulink
12-06 07:46:43.298: INFO/textContent age(831): http://www.submenu.jsp?mn=gx
12-06 07:46:43.298: INFO/currentElementName(831): menulink
12-06 07:46:43.301: INFO/textContent age(831): &
12-06 07:46:43.301: INFO/currentElementName(831): menulink
12-06 07:46:43.301: INFO/textContent age(831): ps=9
12-06 07:46:43.301: INFO/currentElementName(831): menulink
12-06 07:46:43.301: INFO/currentElementName(831): menulink求助，谢谢~~