package com.wo;import android.app.Activity;
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;public class WoActivity extends Activity implements OnClickListener{
private EditText editText1,editText2;
private TextView textView1,textView2,textView3;
private Button button1,button2,button3,button4;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
editText1=(EditText) this.findViewById(R.id.editText1);
editText2=(EditText) this.findViewById(R.id.editText2);
textView1=(TextView) this.findViewById(R.id.textView1);
textView2=(TextView) this.findViewById(R.id.textView2);
textView3=(TextView) this.findViewById(R.id.textView3);
button1=(Button) this.findViewById(R.id.button1);
button2=(Button) this.findViewById(R.id.button2);
button3=(Button) this.findViewById(R.id.button3);
button4=(Button) this.findViewById(R.id.button4);
button1.setOnClickListener(this);
button2.setOnClickListener(this);
button3.setOnClickListener(this);
button4.setOnClickListener(this);
}
@Override
public void onClick(View v) {
// TODO Auto-generated method stub
Button button=(Button)v;
textView1.setText(button.getText());
textView1.setText(button.getText());
int a=Integer.parseInt(editText1.getText().toString());
int b=Integer.parseInt(editText2.getText().toString());
int c=4;
Log.v("a,b", Integer.toString(a)+" "+Integer.toString(b));
Log.v("sdfsdf", Boolean.toString("dsdf".equals("dsdf")));
Log.v("dfsdfsdfsdfsd", button.getText().toString());
if(button.getText().toString()=="+"){
c=a+b;
}else if(button.getText().toString()=="-"){
c=a-b;
}else if(button.getText().toString()=="*"){
c=a*b;
}else if(button.getText().toString()=="/"){
c=a/b;
}
textView2.setText("=");
textView3.setText(c+"");
}
}
为什么我无法判断if里的语句,求解.
还有“==”和equals在比较字符串问题上是等价的么?
能不能在改进一下这个小程序,使它变的更简洁。
import android.os.Bundle;
import android.util.Log;
import android.view.View;
import android.view.View.OnClickListener;
import android.widget.Button;
import android.widget.EditText;
import android.widget.TextView;public class WoActivity extends Activity implements OnClickListener{
private EditText editText1,editText2;
private TextView textView1,textView2,textView3;
private Button button1,button2,button3,button4;
/** Called when the activity is first created. */
@Override
public void onCreate(Bundle savedInstanceState) {
super.onCreate(savedInstanceState);
setContentView(R.layout.main);
editText1=(EditText) this.findViewById(R.id.editText1);
editText2=(EditText) this.findViewById(R.id.editText2);
textView1=(TextView) this.findViewById(R.id.textView1);
textView2=(TextView) this.findViewById(R.id.textView2);
textView3=(TextView) this.findViewById(R.id.textView3);
button1=(Button) this.findViewById(R.id.button1);
button2=(Button) this.findViewById(R.id.button2);
button3=(Button) this.findViewById(R.id.button3);
button4=(Button) this.findViewById(R.id.button4);
button1.setOnClickListener(this);
button2.setOnClickListener(this);
button3.setOnClickListener(this);
button4.setOnClickListener(this);
}
@Override
public void onClick(View v) {
// TODO Auto-generated method stub
Button button=(Button)v;
textView1.setText(button.getText());
textView1.setText(button.getText());
int a=Integer.parseInt(editText1.getText().toString());
int b=Integer.parseInt(editText2.getText().toString());
int c=4;
Log.v("a,b", Integer.toString(a)+" "+Integer.toString(b));
Log.v("sdfsdf", Boolean.toString("dsdf".equals("dsdf")));
Log.v("dfsdfsdfsdfsd", button.getText().toString());
if(button.getText().toString()=="+"){
c=a+b;
}else if(button.getText().toString()=="-"){
c=a-b;
}else if(button.getText().toString()=="*"){
c=a*b;
}else if(button.getText().toString()=="/"){
c=a/b;
}
textView2.setText("=");
textView3.setText(c+"");
}
}
为什么我无法判断if里的语句,求解.
还有“==”和equals在比较字符串问题上是等价的么?
能不能在改进一下这个小程序,使它变的更简洁。
解决方案 »
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