android代码private class ClickListener implements View.OnClickListener{
@Override
public void onClick(View v) {
useridedit = (EditText)findViewById(R.id.userid);
passedit = (EditText)findViewById(R.id.pass);
String userid = useridedit.getText().toString();
String pass = passedit.getText().toString();
String urlstr = "http://172.18.112.151:8080/chatserver/CheckLogin?userid="+userid+"&pass="+pass;
try {
URL url = new URL(urlstr);
HttpURLConnection conn = (HttpURLConnection)url.openConnection();
Log.i("v", urlstr);
Toast.makeText(getApplicationContext(), userid+"", 1).show();
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
/*if(!userid.equals("") && !pass.equals("")){
if(v.getId()==login.getId()){
if(new CheckLogin().check(userid, pass)){
}else{
Toast.makeText(getApplicationContext(), R.string.loginerror, Toast.LENGTH_SHORT).show();
}
}else if(v.getId()==cancel.getId()){
MainActivity.this.finish();
}
}else{
Toast.makeText(getApplicationContext(), R.string.loginvalid, Toast.LENGTH_SHORT).show();
}*/
}
servlet代码:public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
System.out.println("init");
String userid = request.getParameter("userid");
String pass = request.getParameter("pass");
System.out.println(userid+" "+pass);
}问题:为嘛我的servlet里面的System.out.println(userid+" "+pass);什么也没油打印
@Override
public void onClick(View v) {
useridedit = (EditText)findViewById(R.id.userid);
passedit = (EditText)findViewById(R.id.pass);
String userid = useridedit.getText().toString();
String pass = passedit.getText().toString();
String urlstr = "http://172.18.112.151:8080/chatserver/CheckLogin?userid="+userid+"&pass="+pass;
try {
URL url = new URL(urlstr);
HttpURLConnection conn = (HttpURLConnection)url.openConnection();
Log.i("v", urlstr);
Toast.makeText(getApplicationContext(), userid+"", 1).show();
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}
/*if(!userid.equals("") && !pass.equals("")){
if(v.getId()==login.getId()){
if(new CheckLogin().check(userid, pass)){
}else{
Toast.makeText(getApplicationContext(), R.string.loginerror, Toast.LENGTH_SHORT).show();
}
}else if(v.getId()==cancel.getId()){
MainActivity.this.finish();
}
}else{
Toast.makeText(getApplicationContext(), R.string.loginvalid, Toast.LENGTH_SHORT).show();
}*/
}
servlet代码:public void doPost(HttpServletRequest request, HttpServletResponse response)
throws ServletException, IOException {
System.out.println("init");
String userid = request.getParameter("userid");
String pass = request.getParameter("pass");
System.out.println(userid+" "+pass);
}问题:为嘛我的servlet里面的System.out.println(userid+" "+pass);什么也没油打印
2.HttpURLConnection conn = (HttpURLConnection)url.openConnection();
conn.connect();//没看到这个。
我怎么觉得你用System.out.println没用啊...
以前都是用log4j打印的
在浏览器里面试试,是否是通的。
开始时:
String uploadUrl = "http://" + ip+ ":8080/uploadfileservlet/UploadServlet";
result = new FileUploadUtil().uploadFile(picPath, uploadurl);上面这样用有问题,
换成这样了
result = new FileUploadUtil().uploadFile(picPath, "http://" + ip
+ ":8080/uploadfileservlet/UploadServlet");
然后 好了,当时把我搞的一愣一愣的。不知道为啥,你看些下你的,是不是差不多这样
URL url = new URL(urlstr);
HttpURLConnection conn = (HttpURLConnection)url.openConnection();
conn.connect();
Log.i("v", urlstr);
Toast.makeText(getApplicationContext(), userid+"", 1).show();
} catch (MalformedURLException e) {
e.printStackTrace();
} catch (IOException e) {
e.printStackTrace();
}有异常在后台打印出来么?