android 如何用post给后台提交json格式的数据

Question

我这只是用post传过去 但是后台接收有问题 需要提交json格式 求大神 赐教 huoquCode.setClickable(false);
        UIUtils.countdownOneMin(huoquCode);
        String url ="http://192.168.0.151:8080/Platform/sms/captcha.do";
        String phone = et_register_user.getText().toString().trim();
        System.out.print("手机号"+phone);
        OkHttpUtils
                .post()
                .url(url)
                .addParams("phone_number", phone)
                .build()
                .execute(new StringCallback() {
                    @Override
                    public void onResponse(String response, int id) {
                        LogUtils.e("请求返回的数据~~~~~~~~~~~~~~~~~~~~~~~~~~~~~"+response);
                        LogUtils.e(response);
                        Gson gson = new Gson();
                        SendMsmBean sendMsmBean = gson.fromJson(response, SendMsmBean.class);
                        /*if (sendMsmBean.status.equals("0")) {
                            ToastUtil.showShort(getContext(), sendMsmBean.info);
                        }*/
                    }
                    @Override
                    public void onError(Call call, Exception e, int id) {
                        Toast.makeText(getContext(), "失败", Toast.LENGTH_SHORT).show();
                    }
                });    }

Answer 1

我是volley做的web请求，请求体是json，可以参考一下，代码是kotlin，不要问为什么，android只会kotlin...
fun register(
            context: Context,
            email: String,
            password: String,
            complete: (Boolean) -> Unit) {
        val jsonBody = JSONObject()
        jsonBody.put("email", email)
        jsonBody.put("password", password)
        val requestBody = jsonBody.toString()        val registerRequest = object : StringRequest(
                Method.POST,
                URL_REGISTER,
                Response.Listener { response ->
                    println(response)
                    complete(true)
                },
                Response.ErrorListener { error ->
                    Log.d("ERROR", "Could not register user")
                    complete(false)
                }) {
            override fun getBodyContentType(): String {
                return "application/json; charset=utf-8"
            }            override fun getBody(): ByteArray {
                return requestBody.toByteArray()
            }
        }        Volley.newRequestQueue(context).add(registerRequest)
    }

Answer 2

没有语法高亮，只能用java的了
fun register(
            context: Context,
            email: String,
            password: String,
            complete: (Boolean) -> Unit) {
        val jsonBody = JSONObject()
        jsonBody.put("email", email)
        jsonBody.put("password", password)
        val requestBody = jsonBody.toString()        val registerRequest = object : StringRequest(
                Method.POST,
                URL_REGISTER,
                Response.Listener { response ->
                    println(response)
                    complete(true)
                },
                Response.ErrorListener { error ->
                    Log.d("ERROR", "Could not register user")
                    complete(false)
                }) {
            override fun getBodyContentType(): String {
                return "application/json; charset=utf-8"
            }            override fun getBody(): ByteArray {
                return requestBody.toByteArray()
            }
        }        Volley.newRequestQueue(context).add(registerRequest)
    }

Answer 3

看不懂你写的 有android的代码吗？

Answer 4

这就是android的代码啊，以后java在安卓的开发迟早会被Kotlin取代的，尽早掌握语法也不是坏事，因为不喜欢java，就没学过

Answer 5

看样子用的是hongyang大神的okhttputil，参考链接
json string的话用以下代码OkHttpUtils
    .postString()
    .url(url)
    .content(new Gson().toJson(new PhoneBean(phone)))
    .build()
    .....PhoneBean是需要传递的数据的类public class PhoneBean{
    private String phone_number;
    public PhoneBean(String phone_number) {
        this.phone_number= phone_number;
    }
    public String getPhone_number() {
        return phone_number;
    }    public void setPhone_number(String phone_number) {
        this.phone_number= phone_number;
    }}如果有多个参数，就添加多个参数并设置值进行传递

Answer 6

用Gson的 toJson()方法

Answer 7

可以试试volley，谷歌的官方库，现在你用的web请求库已经不维护了

Answer 8

为什么不试着将json字符串放在body体中post到后台呢？这很简单啊！