聚合API返回的json解析困难，求大佬帮忙看一下

Question

json如下，只是小部分，后面还有CDEF想把result解析为list结构
{
    "reason": "成功返回",
    "result": {
        "A": [
            {
                "id": "2000386",
                "big_ppname": "AC",
                "pin": "A"
            },
            {
                "id": "2000142",
                "big_ppname": "阿尔法-罗密欧",
                "pin": "A"
            }
        ],
        "B": [
            {
                "id": "2000194",
                "big_ppname": "奔驰",
                "pin": "B"
            },
            {
                "id": "2000198",
                "big_ppname": "标致",
                "pin": "B"
            }
        ]
    },
    "error_code": 0
}求大神告知如何把这段json转化为实体类，把result转为list

Answer 1

Bean代码public class TestBean {
    private String reason;
    private List<TBean> result;
    private int error_code;    public String getReason() {
        return reason;
    }    public void setReason(String reason) {
        this.reason = reason;
    }    public List<TBean> getResult() {
        return result;
    }    public void setResult(Map<String, List<TBean>> map) {
        this.result = new ArrayList<>();
        if (map != null) {
            for (Map.Entry<String, List<TBean>> entry : map.entrySet()) {
                System.out.println("Key = " + entry.getKey() + ", Value = " + entry.getValue());
                if (entry.getValue() != null){
                    result.addAll(entry.getValue());
                }
            }
        }
    }    public int getError_code() {
        return error_code;
    }    public void setError_code(int error_code) {
        this.error_code = error_code;
    }    public static class TBean {
        private String id;
        private String big_ppname;
        private String pin;        public String getId() {
            return id;
        }        public void setId(String id) {
            this.id = id;
        }        public String getBig_ppname() {
            return big_ppname;
        }        public void setBig_ppname(String big_ppname) {
            this.big_ppname = big_ppname;
        }        public String getPin() {
            return pin;
        }        public void setPin(String pin) {
            this.pin = pin;
        }
    }
}我用的fastjson解析
测试代码TestBean testBean = JSON.parseObject(str,TestBean.class);
Log.d("TestBean", JSON.toJSONString(testBean));日志输出D/TestBean: {"error_code":0,"reason":"成功返回","result":[{"big_ppname":"奔驰","id":"2000194","pin":"B"},{"big_ppname":"标致","id":"2000198","pin":"B"},{"big_ppname":"AC","id":"2000386","pin":"A"},{"big_ppname":"阿尔法-罗密欧","id":"2000142","pin":"A"}]}

Answer 2

百度一下 GsonFormat

Answer 3

用GsonFormat，自动创建javaBean，前提是保证json格式正确，然后代码里把json字符串传进去就行了，之后数据的获取就是从刚才的javaBean对象中通过get方法取出就行了。需要注意的就是有些字段不适合做变量属性名，需要添加别名，GsonFormat也自动创建好了，调用的时候注意一下就好了。