新手提问：怎样让gridview里头能够出现一个对应于每一行可以输入密码的列呢？

Question

如题，我现在只能建立一个templefield但不能往上头写字啊！怎么设置阿该？

Answer 1

<asp:TemplateField >
                                    <itemstyle width="15%" horizontalalign="Left" />
                                    <headerstyle width="15%" horizontalalign="Center" />
                                    <itemtemplate>
                        <asp:TextBox id="txtpwd" runat="server" TextMode="password"></asp:TextBox>
                            </itemtemplate>
                                </asp:TemplateField>

Answer 2

pwd = this.GridView1.Rows[e.RowIndex].Cells[7].Text;
用以上语句得到的是一个"",该怎么去正确读取阿？

Answer 3

TextBox txtPwd=(TextBox)this.gridview1.row.cells[0].FindControl("txtpwd");
string pwd;
pwd=txtpwd.Text;

Answer 4

TextBox txtPwd=(TextBox)this.GridView1.Rows[e.RowIndex].Cells[7].FindControl("txtpwd");
string pwd;
pwd=txtpwd.Text;

Answer 5

给段代码你：    <asp:Button ID="Button1" runat="server" OnClick="Button1_Click2" Text="添加" />
    <asp:GridView ID="gdvMain" runat="server" AutoGenerateColumns="False" OnRowEditing="gdvMain_RowEditing" OnRowCancelingEdit="gdvMain_RowCancelingEdit" OnRowUpdating="gdvMain_RowUpdating" OnRowDataBound="gdvMain_RowDataBound">
        <Columns>
            <asp:TemplateField HeaderText="编号">
                <ItemTemplate>
                    <%#Eval("ID")%>
                </ItemTemplate>
                <EditItemTemplate>
                    <asp:TextBox ID="txtID" runat="server" Text='<%#Eval("ID")%>'/>
                </EditItemTemplate>
            </asp:TemplateField>
            <asp:TemplateField HeaderText="名称">
                <ItemTemplate>
                    <%#Eval("Name")%>
                </ItemTemplate>
                <EditItemTemplate>
                    <asp:DropDownList ID="drpName" runat="server"/>
                </EditItemTemplate>
            </asp:TemplateField>
            <asp:CommandField ButtonType="Button" HeaderText="编辑" ShowEditButton="True" />
        </Columns>
    </asp:GridView>
        protected void gdvMain_RowCancelingEdit(object sender, GridViewCancelEditEventArgs e)
        { 
            this.gdvMain.EditIndex = -1;
            BindGridView();
        }        protected void gdvMain_RowEditing(object sender, GridViewEditEventArgs e)
        {
            if (((DropDownList)gdvMain.Rows[e.NewEditIndex].FindControl("drpName")) != null)
            {
                DropDownList drpName = ((DropDownList)gdvMain.Rows[e.NewEditIndex].FindControl("drpName"));
                drpName.DataSource = GetDataFromXML("names");
                drpName.DataBind();
            }            this.gdvMain.EditIndex = e.NewEditIndex;
            this.gdvMain.EditRowStyle.BackColor = Color.FromName("#f7ce90");
            BindGridView();
        }        protected void gdvMain_RowUpdating(object sender, GridViewUpdateEventArgs e)
        {
            int id = Convert.ToInt32(((TextBox)this.gdvMain.Rows[e.RowIndex].FindControl("txtID")).Text);
            string name = Convert.ToString(((DropDownList)this.gdvMain.Rows[e.RowIndex].FindControl("drpName")).Text);
            Data dtt = new Data();
            dtt.ID = id;
            dtt.Name = name;            UpdateData(dtt);            this.gdvMain.EditIndex = -1;
            BindGridView();
        }

Answer 6

TextBox txtPwd=(TextBox)this.gridview1.row.cells[0].FindControl("txtpwd");
string pwd;
pwd=txtpwd.Text;用这个也不行，提示服务器错，GridView”并不包含“row”的定义

Answer 7

编译错误 
说明: 在编译向该请求提供服务所需资源的过程中出现错误。请检查下列特定错误详细信息并适当地修改源代码。 编译器错误信息: CS0103: 当前上下文中不存在名称“txtpwd”源错误: 行 70:         TextBox txtPwd = (TextBox)this.GridView1.Rows[e.RowIndex].Cells[7].FindControl("txtpwd");
行 71: 
行 72:         pwd = txtpwd.Text;
行 73: 
行 74:         st2 = tjrq.ToShortDateString() + " " +stime.ToShortTimeString();