返回结果的方法
private static string GetExceptionPoint(XmlNode node)
{
XmlDocument xmldoc = new XmlDocument();
XmlElement root = xmldoc.CreateElement("root");
XmlElement el;
for (int i = 0; i < node.ChildNodes.Count; i++)
{
el = xmldoc.CreateElement("item");
el.SetAttribute("label", GetLabelName(node.ChildNodes[i].Attributes["label"].Value)//调用下面的方法);
if (node.ChildNodes[i].Attributes["outside"] != null) el.SetAttribute("val", "超厚");
else el.SetAttribute("val", node.ChildNodes[i].Attributes["val"].Value.Split(',')[0]);
root.AppendChild(el);
}
return root.InnerXml;
}//重新设置节点的名称和值
private static string GetLabelName(string str)
{
string[] labs = "L,M,D,LA,E,LB,F,LC,G,H,I,RC,J,RB,K,RA,N".Split(',');
string[] names = "右前翼子板,引擎盖,左前翼子板,左A柱,左前门,左B柱,左后门,左C柱,左后翼子板,行李箱盖,右后翼子板,右C柱,右后门,右B柱,右前门,右A柱,车顶".Split(',');
for (int i = 0; i < labs.Length; i++)
{
if (str == labs[i]) return names[i];
}
return "";
}
现在我在外面定义了一个字符串变量 来接受上面返回的 root.InnerXml(还有更好的办法么?),如下:
string jzd = GetExceptionPoint(root["fg"]);问题来了,现在我不知道怎么把这里面的值一一取出来赋值给lab标签了,我要的结果如下; <p class="name"><span class="dance">右前翼子板:</span><span>lab</span></p><br />
<p class="name"><span class="dance">引擎盖:</span><span>lab</span></p><br />
<p class="name"><span class="dance">左前翼子板:</span><span>lab</span></p><br />
<p class="name"><span class="dance">左A柱:</span><span>lab</span></p><br />
<p class="name"><span class="dance">左前门:</span><span>lab</span></p><br />
<p class="name"><span class="dance">左B柱:</span><span>lab</span></p><br />
<p class="name"><span class="dance">左后门:</span><span>lab</span></p><br />
<p class="name"><span class="dance">左C柱:</span><span>lab</span></p><br />
<p class="name"><span class="dance">左后翼子板:</span><span>lab</span></p><br />
<p class="name"><span class="dance">行李箱盖:</span><span>lab</span></p><br />
<p class="name"><span class="dance">右后翼盖子板:</span><span>lab</span></p><br />
<p class="name"><span class="dance">右C柱:</span><span>95</span></p><br />
<p class="name"><span class="dance">右后门:</span><span>95</span></p><br />
<p class="name"><span class="dance">左B柱:</span><span>95</span></p><br />
<p class="name"><span class="dance">右前门:</span><span>95</span></p><br />
<p class="name"><span class="dance">右A柱:</span><span>95</span></p><br />
<p class="name"><span class="dance">车顶:</span><span>95</span></p><br />
那你就
private static XmlNodeList GetExceptionPoint(XmlNode node)
{
XmlDocument xmldoc = new XmlDocument();
XmlElement root = xmldoc.CreateElement("root");
XmlElement el;
for (int i = 0; i < node.ChildNodes.Count; i++)
{
el = xmldoc.CreateElement("item");
el.SetAttribute("label", GetLabelName(node.ChildNodes[i].Attributes["label"].Value)//调用下面的方法);
if (node.ChildNodes[i].Attributes["outside"] != null) el.SetAttribute("val", "超厚");
else el.SetAttribute("val", node.ChildNodes[i].Attributes["val"].Value.Split(',')[0]);
root.AppendChild(el);
}
return root.ChildNodes;
}
不要返回String,返回XmlNodeList,然后循环遍历绑定
如:
for (int i = 0; i < NodeList.Count; i++)
{
if ("你的匹配条件")//NodeList[i].ChildNodes[1].Name=="outside"什么的
{
//你自己的绑定
}
}