在GridView中 有没有好的方法根据rows中某个字段值确定它可不可以编辑同删除

Question

如GridView表:
 编辑   序号   班级   学号     学科   分数  删除
 编辑   1      306    22898    9      119   删除
 编辑   2      306    22898    8      139   删除
 编辑   3      306    22898    6      107   删除 
 编辑   4      306    22898    7      110   删除 
 编辑   5      306    22898    5      98    删除 
 编辑   6      306    22898    1      121   删除 那么我要规定在学科为1的记录不能删除如何做最好有啥好的设置方法  大家帮忙

Answer 1

protected void GridView1_RowDataBound(object sender, GridViewRowEventArgs e)
    {
        if (e.Row.RowType == DataControlRowType.DataRow)
        {
string temp=e.Row.Cells[4].Text.Trim();
switch(temp)
{
 case "1": e.Row.Cells[6].Enabled=false;
}
}
}

Answer 2

楼上正解.
case 后面加个break;就可.

Answer 3

protected void GridView1_RowDataBound(object sender, GridViewRowEventArgs e)
        {
            if (e.Row.RowIndex >= 0)
            {
                if (e.Row.RowType == DataControlRowType.DataRow)
                {                    Label lbQty = e.Row.Cells[6].FindControl("lb_Qty") as Label;
                    Label lbSet = e.Row.Cells[7].FindControl("lb_Set") as Label;                    int qty = 0;
                    int set = 0;
                    if (lbQty != null && (lbQty.Text.Trim() != "" || lbQty.Text.Trim() != string.Empty) && lbSet != null && (lbSet.Text.Trim() != "" || lbSet.Text.Trim() != string.Empty))
                    {
                        qty = Convert.ToInt32(lbQty.Text.Trim());
                        set = Convert.ToInt32(lbSet.Text.Trim());                        if (qty < set)
                        {
                            e.Row.BackColor = System.Drawing.Color.Red;
                            btnChange.Enabled = false;
                        }
                    }
                    else
                    {
                        btnChange.Enabled = false;
                    }
                                     }
            }
        }

Answer 4

再RowDataBound事件内判断条件就可以了,

Answer 5

1.
方法 1 同 sosohehe2。
方法 2 如下：<asp:templatefield>
<itemtemplate>
<asp:linkbutton id=btnDelete commandname=delete enabled='<%# (int)Eval("学科") != 1 %>'
</itemtemplate>
</asp:templatefield>

Answer 6

if ((HyperLink)e.Row.FindControl("hyperlink") != null)
        {
            if (e.Row.Cells[15].Text == "待收货")
            {
                ((HyperLink)e.Row.FindControl("hyperlink")).Text = "<a color='#333333'>待收货</a>";
            }
            else if(e.Row.Cells[15].Text == "已入库")
            {
                ((HyperLink)e.Row.FindControl("hyperlink")).Text = "<a><font color='#000FFF'>已入库</font></a>";
            }
            else
            {
                ((HyperLink)e.Row.FindControl("hyperlink")).Text = "<Font color='red'>已收货</Font>";
                ((HyperLink)e.Row.FindControl("hyperlink")).NavigateUrl = "Javascript:launchmodule(600,450,'../AssetApply4/Asset_InsertDevices.aspx?OrderListID="+e.Row.Cells[1].Text+"',0,0,0)";
            }
        }  if ((HyperLink)e.Row.FindControl("hyperlink") != null)
        {
            if (e.Row.Cells[15].Text == "待收货")
            {
                ((HyperLink)e.Row.FindControl("hyperlink")).Text = "<a color='#333333'>待收货</a>";
            }
            else if(e.Row.Cells[15].Text == "已入库")
            {
                ((HyperLink)e.Row.FindControl("hyperlink")).Text = "<a><font color='#000FFF'>已入库</font></a>";
            }
            else
            {
                ((HyperLink)e.Row.FindControl("hyperlink")).Text = "<Font color='red'>已收货</Font>";
                ((HyperLink)e.Row.FindControl("hyperlink")).NavigateUrl = "Javascript:launchmodule(600,450,'../AssetApply4/Asset_InsertDevices.aspx?OrderListID="+e.Row.Cells[1].Text+"',0,0,0)";
            }
        }

Answer 7

在ItemDataBound事件中判断~
Jinglecat(晓风残月 >> 问题需简洁，错误要详细)的方法也可以

Answer 8

最简便的方式:在删除或编辑前,判断学科是否为"1":
if (dataGridView.Rows[e.RowIndex].Cells["学科"].Value.ToString().Trim() != "1")
{
   // 不为"1",删除或编辑
}