如题,在线等,马上给分!

解决方案 »

  1.   

    <html>
    <body onload="document.body.scrollTop=document.body.scrollHeight"><p>as
      sdasd
      sdasd
    sda</p>
    <p>&nbsp;</p>
    <p>&nbsp;</p>
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    <p>&nbsp;</p>
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    <p>sd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasddasd
      sdasd
      sdasd
      
      sdasd
      sdasd
      sdasdsdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
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      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd
      sdasd </p>
    </body>
    </html></body>
      

  2.   

    <html>
    <body>
    <input type="button"  value ="记得结贴哦" onclick="document.body.scrollTop=document.body.scrollHeight">
    <p>as
      sdasd
      sdasd
    sda</p>
    <p>&nbsp;</p>
    <p>&nbsp;</p>
    <p>&nbsp;</p>
    <p>&nbsp;</p>
    <p>&nbsp;</p>
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    <p>&nbsp;</p>
    <p>sd
     </p>
    </body>
    </html>
      

  3.   

    <asp:button ......
    服务器控件
      

  4.   

    aspx代码
    =======
    <HTML>
    <HEAD>
    <script>
    function GoEnd() 

    document.body.scrollTop=document.body.scrollHeight 

    }

    </script>
    </HEAD>
    <BODY>
    <form runat="server">
    <asp:Button id="Button1" runat="server" Text="Button"></asp:Button>
    <P></P>
    <p>&nbsp;</p>
    <p>&nbsp;</p>
    <p>&nbsp;</p>
    <p>&nbsp;</p>
    <p>
    <p>&nbsp;</p>
    <p>&nbsp;</p>
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    <p>&nbsp;</p>
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    <p>&nbsp;</p>
    <p>&nbsp;</p>
    <p>sd
    </p>
    </form>
    </BODY>
    </HTML>
    ==================================
    aspx.cs        private void Button1_Click(object sender, System.EventArgs e)
            {
                this.Page.RegisterStartupScript("onload","<script language=javascript>"+"GoEnd()"+"</script>");        }
      

  5.   

    我现在用的方法是,在OnClientClick中滚动至底部,再设置MaintainScrollPositionOnPostback="true"
      

  6.   

    没问题的答案:
    aspx
    ============
    <HTML>
    <HEAD>
    <script> function GoEnd() 

    document.getElementById("cc").scrollIntoView(); 

    </script>
    </HEAD>
    <BODY>

    <form runat="server">
    <asp:Button id="Button1" runat="server" Text="Button"></asp:Button>
    <p>&nbsp;</p>
    <p>&nbsp;</p>
    <p>&nbsp;</p>
    <p>&nbsp;</p>
    <p>&nbsp;</p>
    <p>&nbsp;</p>
    <p>&nbsp;</p>
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    <p>&nbsp;</p> <p>&nbsp;</p>
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    <p>&nbsp;</p>
    <p>&nbsp;</p>
    <a name="cc" style="display:none">sdfsdfsdf</a>
    </form>
    </BODY>
    </HTML>======================
    aspx.cs        private void Button1_Click(object sender, System.EventArgs e)
            {
                this.Page.RegisterStartupScript("onload","<script language=javascript>"+"GoEnd()"+"</script>");        }
      

  7.   

    在页面最底部加入Ahthor <a id="A"></a>假设该a的索引为y(页面中第一次出现为0,第二次为1...)用Ajax写
    function linkTo(y)
    {
    var x=window.open("aa.aspx","","");
    x.location.hash=y;
    }
    在onclick中ClientScript.RegisterStartupScript(this.GetType(), "", "<script>linkTo(y);</script>");记得把y值改为索引号
      

  8.   

    zhulei2008(滴水浪流)
    你的方法我试了下,回发后就又变回去了
      

  9.   

    var x=window.open("aa.aspx","","");
    这样还能是PostBack吗?
      

  10.   

    可以了,马上给你分
    忘了设回MaintainScrollPositionOnPostback="False"了