关于反射如何获得类的属性参数（表达可能不太正确，请大家看代码）？？【在线等】

Question

[Serializable]
[TableName("tUser")]
public class User
{}
……………………………………
通过反射如何得到User类的TableName属性中的"tUser"的值~??

Answer 1

http://community.csdn.net/Expert/TopicView3.asp?id=5415216

Answer 2

using System;
using System.Reflection;
using System.Threading;namespace ConsoleApplication1
{
    class Program
    {
        static void Main(string[] args)
        {
            GetAttributeValue(new Exa());            Console.ReadKey();
        }        static void GetAttributeValue(object obj)
        {
            Type type = obj.GetType();            PropertyInfo[] pis = type.GetProperties();  // 获取此对象所有属性.
            foreach (PropertyInfo pi in pis)
            {
                object[] objs = pi.GetCustomAttributes(true);   // 这里获取每个属性的自定义属性(Attribute).
                foreach (object o in objs)
                {
                    Console.WriteLine(o.GetType().FullName);
                    Console.WriteLine(((ValueAttribute)o).Value);
                }
            }
        }
    }    class Exa
    {
        [Value("This is a example")]
        public string Content
        {
            get { return "Content Value"; }
            set { }
        }        public string Name
        {
            get { return "Name Value"; }
            set { }
        }
    }    class ValueAttribute : Attribute
    {
        string s = "";        public ValueAttribute(string str)
        {
            s=str;
        }        public string Value
        {
            get{return s;}
        }
    }
}

Answer 3

User user = new User();
            object[] objs = user.GetType().GetCustomAttributes(typeof(TableNameAttribute), false);
            foreach (object obj in objs)
            {
                TableNameAttribute tn = (TableNameAttribute)obj;
//tn.属性
            }

Answer 4

        static void GetAttributeValue(object obj)
        {
            Type type = obj.GetType();            PropertyInfo[] pis = type.GetProperties();  // 获取此对象所有属性.
            foreach (PropertyInfo pi in pis)
            {
                object[] objs = pi.GetCustomAttributes(true);   // 这里获取每个属性的自定义属性(Attribute).
                foreach (object o in objs)
                {
                    Console.WriteLine(o.GetType().FullName);
                    Console.WriteLine(((ValueAttribute)o).Value);
                }
            }
        }

Answer 5

例如：[....]
class TableNameAttribute:Attribute
{
  public Name;
  public TableName(string Name){ this.Name=Name;}
}程序中：TableNameAttribute tn=(TableNameAttribute)Attribute.GetCustomAttribute(
  typeof(User),typeof(TableNameAttribute));
if(tn!=null)
{
  string result=tn.Name;
  ......