怎么让xml.Load获取到404页面不出错啊？

Question

        XmlDocument xml = new XmlDocument();
        xml.Load("http://www.youdao.com/smartresult-xml/search.s?type=ip&q=" + userIP);
        string addr_name = xml.SelectSingleNode("//product/location").InnerText;
        //return addr_name.Substring(0, 2);
        Response.Write(addr_name);假如URL是错的，就会出现错误页面，请问有没有办法不显示错误，获取得到数据就获取得到，获取不到就算了不用提示出来。

Answer 1

try
{
        XmlDocument xml = new XmlDocument();
        xml.Load("http://www.youdao.com/smartresult-xml/search.s?type=ip&q=" + userIP);
        string addr_name = xml.SelectSingleNode("//product/location").InnerText;
        //return addr_name.Substring(0, 2);
        Response.Write(addr_name);
}
catch { }